我有以下查询:
select s.ScreenID, s.ScreenName, ps.ScheduleDate
from Screens s
left join PerformanceSchedules ps on ps.ScreenID = s.ScreenID
where s.TheatreID = 2 and ((ps.ScheduleDate not between convert(datetime, '2019-08-02 14:00:00.000') and convert(datetime, '2019-08-02 20:00:00.000')) or (ps.ScheduleDate is null))
查询的结果是:
ScreenID ScreenName ScheduleDate
4 Screen 1 2019-08-02 15:00:00.000
5 Screen 2 2019-08-02 15:00:00.000
6 Screen 3 NULL
通常它应该只返回屏幕3,而不是其他两个,因为两者的ScheduleDate是在时间跨度。
结果应该是:
6 Screen 3 NULL
我怀疑你真正想要的:
select s.ScreenID, s.ScreenName, ps.ScheduleDate
from Screens s left join
PerformanceSchedules ps
on ps.ScreenID = s.ScreenID and
ps.ScheduleDate between convert(datetime, '2019-08-02 14:00:00.000', 121) and convert(datetime, '2019-08-02 20:00:00.000', 121)
where s.TheatreID = 2 and
ps.ScreenID is null;
这将返回有那些时间之间没有计划日期的屏幕。