我正在使用以下方法来处理我的请求
override fun intercept(chain: Interceptor.Chain): Response = chain.proceed(chain.request())
.let { originalResponse ->
Log.i("AMIRA999", "code : " + originalResponse.code())
when (originalResponse.code()) {
200 -> {
Log.i("AMIRA999", "body : " + getErrorResponse(originalResponse))
originalResponse
}
401, 404 -> {
Log.i("AMIRA999", "body : " + getErrorResponse(originalResponse))
originalResponse
/*return originalResponse.mapToBody(
originalResponse.body()?.contentType(),
getErrorResponse(originalResponse)
)*/
}
else -> {
Log.i("AMIRA999", "body : " + originalResponse.body().toString())
throw BadRequestException()
}
}
}
该方法在代码为200时工作完美,但是如果代码为404或401,则会崩溃
我需要继续返回的json来自服务器,并且不会崩溃以能够通过错误消息进行处理
我该怎么做?
我得到的崩溃是以下
retrofit2.HttpException: HTTP 401 UNAUTHORIZED
at com.jakewharton.retrofit2.adapter.kotlin.coroutines.CoroutineCallAdapterFactory$BodyCallAdapter$adapt$2.onResponse(CoroutineCallAdapterFactory.kt:104)
at retrofit2.OkHttpCall$1.onResponse(OkHttpCall.java:129)
at okhttp3.RealCall$AsyncCall.execute(RealCall.java:206)
at okhttp3.internal.NamedRunnable.run(NamedRunnable.java:32)
at java.util.concurrent.ThreadPoolExecutor.runWorker(ThreadPoolExecutor.java:1162)
at java.util.concurrent.ThreadPoolExecutor$Worker.run(ThreadPoolExecutor.java:636)
at java.lang.Thread.run(Thread.java:764)
if (response.isSuccessful) {
deferred.complete(response.body()!!)
} else {
deferred.completeExceptionally(HttpException(response))
}