我是Android和Java的新手,正在尝试制作基于位置的应用程序。
编辑
我编写了非常简单的测试代码,并得到了相同的错误。这是java:
package com.example.viewmodeltest;
import androidx.appcompat.app.AppCompatActivity;
import androidx.lifecycle.ViewModel;
import androidx.lifecycle.ViewModelProvider;
import android.os.Bundle;
public class MainActivity extends AppCompatActivity {
public class MyViewModel extends ViewModel {
public int scoreTeamA = 0;
}
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
MyViewModel locationViewModel = new ViewModelProvider(this).get(MyViewModel.class);
}
}
我遇到相同的错误。这是我的应用程序级别build.gradle中的依赖项:
dependencies {
implementation fileTree(dir: 'libs', include: ['*.jar'])
implementation 'androidx.appcompat:appcompat:1.1.0'
implementation 'androidx.constraintlayout:constraintlayout:1.1.3'
testImplementation 'junit:junit:4.12'
androidTestImplementation 'androidx.test.ext:junit:1.1.1'
androidTestImplementation 'androidx.test.espresso:espresso-core:3.2.0'
//dependencies for ViewModel, LiveData, etc.
def lifecycle_version = "2.2.0"
def arch_version = "2.1.0"
// ViewModel
implementation "androidx.lifecycle:lifecycle-viewmodel:$lifecycle_version"
// LiveData
implementation "androidx.lifecycle:lifecycle-livedata:$lifecycle_version"
// Lifecycles only (without ViewModel or LiveData)
implementation "androidx.lifecycle:lifecycle-runtime:$lifecycle_version"
// Saved state module for ViewModel
implementation "androidx.lifecycle:lifecycle-viewmodel-savedstate:$lifecycle_version"
// Annotation processor
annotationProcessor "androidx.lifecycle:lifecycle-compiler:$lifecycle_version"
}
原始帖子
我正在尝试使用ViewModel和LiveData更新用户位置,因为我了解这是了解生命周期的最佳方法。我有默认的地图活动...
public class MapsActivity extends AppCompatActivity implements OnMapReadyCallback {...}
扩展LiveData以存储用户位置的类...
public class LocationLiveData extends LiveData<Location> {
private final Context context;
private FusedLocationProviderClient fusedLocationClient;
private LocationRequest locationRequest;
public LocationLiveData(Context context) {
this.context = context;
this.fusedLocationClient = LocationServices.getFusedLocationProviderClient(context);
}
private void setLocationData(Location location) {
Location value = new Location("SetInternal");
value.setLatitude(location.getLatitude());
value.setLongitude(location.getLongitude());
setValue(value);
}
protected void createLocationRequest() {
LocationRequest locationRequest = LocationRequest.create();
locationRequest.setInterval(1000);
locationRequest.setFastestInterval(500);
locationRequest.setPriority(LocationRequest.PRIORITY_HIGH_ACCURACY);
}
private LocationCallback locationCallback = new LocationCallback() {
@Override
public void onLocationResult(LocationResult locationResult) {
if (locationResult == null) {
return;
}
for (Location location : locationResult.getLocations()) {
setLocationData(location);
}
}
};
private void startLocationUpdates() {
createLocationRequest();
fusedLocationClient.requestLocationUpdates(locationRequest,
locationCallback,
Looper.getMainLooper());
}
@Override
protected void onInactive() {
super.onInactive();
fusedLocationClient.removeLocationUpdates(locationCallback);
}
@Override
protected void onActive() {
super.onActive();
fusedLocationClient.getLastLocation()
.addOnSuccessListener(new OnSuccessListener<Location>() {
@Override
public void onSuccess(Location location) {
if (location != null)
setValue(location);
}
});
startLocationUpdates();
}
}
和一个扩展ViewModel的类,以允许主要活动到达LocationLiveData。
public class LocationViewModel extends ViewModel {
private LocationLiveData locationLiveData;
public LocationViewModel () {
locationLiveData = new LocationLiveData(getApplicationContext());
}
public LocationLiveData getLocationLiveData() {
return locationLiveData;
}
}
然后,当我尝试在onMapReady方法中创建locationViewModel的实例时:
LocationViewModel locationViewModel = new ViewModelProvider(this).get(LocationViewModel.class);
我在该行出现错误:
无法创建com.example.MapsActivity $ LocationViewModel类的实例
原因:java.lang.InstantiationException:java.lang.Class没有零参数构造函数
即使我完全在locationViewModel中取出构造函数,也尝试改为扩展AndroidViewModel,我都会收到此错误。
有什么想法吗?我见过其他类似的查询,但答案一直是从构造函数中取出参数-我已经完成了!
非常感谢您的帮助
任一:
将MyViewModel
移动到单独的Java文件,或
使MyViewModel
为static class
现在,您已将MyViewModel
定义为MainActivity
的内部类。这将不起作用,因为只有MainActivity
的实例才能创建MyViewModel
的实例。特别地,ViewModelProvider
无法创建MyViewModel
的实例。
写作时
public class MainActivity extends AppCompatActivity {
public class MyViewModel extends ViewModel {
public int scoreTeamA = 0;
}
}
这使MyViewModel
成为MainActivity
的内部类,意味着它隐含了对外部类的引用(根据Java documentation),并且不能与MainActivity
分开构造。这实际上意味着在字节码中,即使您不写出该构造函数,其构造函数也始终采用MainActivity
的实例。
您可以通过添加static
关键字使内部类成为静态嵌套类。这将删除对外部类的隐式引用,并使它类似于任何其他顶级类:
public class MainActivity extends AppCompatActivity {
public static class MyViewModel extends ViewModel {
public int scoreTeamA = 0;
}
}