Laravel循环通过特定条件显示前2

问题描述 投票:1回答:1

我期待展示小组赛(想想世界杯)并突出赢家/输家。我试图每年展示每组中的前两支球队。

 $groupbwins = LoserData::select('team')->where('stage', 'group')->where('stageSeries', 'B')->where('ar', $id)->where('win', '1')->take('2')->get();

take(2)产生每个拥有Win的团队中的前两个团队,但不是每个团队获胜最多的团队。如何通过throughand循环显示获得最多胜利的团队(尝试过orderby和groupby,但无法使其工作)或者我是否需要重新安排数据库以便每个团队列出团队中的获胜者作为获胜的团队那个小组中的第一个?

mysql database laravel
1个回答
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投票
+----+----+------+-------+------------+-------------+
| id | ar | win  | stage | team       | stageSeries |
+----+----+------+-------+------------+-------------+
|  1 | 1  |    1 | group | carlton    | B           |
|  2 | 1  |    1 | group | carlton    | B           |
|  3 | 1  |    1 | group | west coast | C           |
|  4 | 1  |    0 | group | west coast | C           |
|  5 | 1  |    1 | group | west coast | B           |
|  6 | 1  |    0 | group | carlton    | A           |
|  7 | 1  |    1 | group | west coast | A           |
|  8 | 1  |    1 | group | carlton    | B           |
|  9 | 1  |    1 | group | carlton    | A           |
| 10 | 1  |    0 | group | west coast | C           |
| 11 | 1  |    0 | group | west coast | C           |
| 12 | 1  |    1 | group | west coast | A           |
| 13 | 1  |    1 | group | carlton    | A           |
| 14 | 1  |    1 | group | west coast | B           |
| 15 | 1  |    1 | group | west coast | B           |
| 16 | 1  |    1 | group | carlton    | B           |
| 17 | 1  |    1 | group | hawthorn   | B           |
| 18 | 1  |    1 | group | hawthorn   | B           |
| 19 | 1  |    1 | group | hawthorn   | A           |
+----+----+------+-------+------------+-------------+

您可以使用此Eloquent构建器:

LoserData::selectRaw('team, sum(win) as winTotal')
  ->where('stage', 'group')
  ->where('stageSeries', 'B')
  ->where('ar', 1)
  ->groupBy('team')
  ->orderBy('winTotal', 'desc')
  ->take('2');

哪个会产生这个查询:

select team, sum(win) as winTotal from `loser_datas` where `stage` = ? and `stageSeries` = ? and `ar` = ? group by `team` order by `winTotal` desc limit 2
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