NgRx操作有效负载未达到效果-没有错误

问题描述 投票:0回答:1

我已经检查了SO的所有可能答案,但似乎无法正确解决此问题。

我正在将有效负载传递给操作'GetUser'。

我希望此有效负载通过效果传递,并最终通过http请求发送到API,但是似乎根本没有触及我的效果。控制台或ngrx开发工具中什么都没有。

我的代码看起来不错,我没有编译错误-怎么了?

这里是效果:

    @Injectable()
    export class LoginEffects {

      env = environment;

      constructor(private actions: Actions, private http: HttpClient, private store: Store<any>) {
      }

      @Effect()
      getUser$: Observable<Action> = this.actions.pipe(
        ofType<GetUser>(LoginActions.GET_USER),
        switchMap((action) => {

          console.warn(action.payload);
          console.warn(action.payload);
          console.warn(action.payload);

          return this.http.post(this.env.urlDefault + '/authenticate', action.payload).pipe(
              map((data) => new LoginActions.GetUserSuccess( data )),
              catchError(error => of(new LoginActions.GetUserFail( error ))));
          }));
    }

这里是动作:

import { Action } from '@ngrx/store';

export const GET_USER = 'GET_USER';
export const GET_USER_FAIL = 'GET_USER_FAIL';
export const GET_USER_SUCCESS = 'GET_USER_SUCCESS';

export class GetUser implements Action {
  readonly type = GET_USER;

  constructor(public payload: any) {
    console.log('GetUser Action Hit!');
  }
}

export class GetUserFail implements Action {
  readonly type = GET_USER_FAIL;

  constructor(public payload: any) {
    console.log('GetUserFail Action Hit!');
  }
}

export class GetUserSuccess implements Action {
  readonly type = GET_USER_SUCCESS;

  constructor(public payload: object) {
    console.log('GetUserSuccess Action Hit!');
  }
}

export type LoginActions = GetUser | GetUserFail | GetUserSuccess;
angular ngrx ngrx-store ngrx-effects
1个回答
1
投票

您是否已在模块中注册效果?将以下行添加到模块导入部分

@NgModule({
  imports: [
    ...
    EffectsModule.forRoot([AppEffects])
  ],
   ...
})
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