如何防止在碰撞时使用相同脚本破坏游戏对象?

问题描述 投票:0回答:1

当玩家对其中一个游戏对象进行攻击时,所有游戏对象(敌人)都会被摧毁。我希望它能够摧毁游戏对象(敌人),如果它与当前的游戏对象发生碰撞,而其他的则不会被摧毁。所有的敌人都有相同的剧本。


这是附加在 MainCharacter 游戏对象中的运动脚本..

public class Movement : MonoBehaviour
{
    public float movementSpeed = 6.0f;
    public GameObject player;
    public int jumpHeight = 350;
    private bool onGround = false;
    private bool afterMovingPlatform = false;
    Animator anim;

    //// Use this for initialization
    void Start()
    {
        anim = GetComponent<Animator>();
        player = GetComponent<GameObject>();
    }

    void Update()
    {
        //these are the codes for keyboard inputs when walking, attacking, etc...
    }

    void OnCollisionEnter2D(Collision2D coll)
    {
        if (coll.gameObject.tag == "Ground")
        {
            onGround = true;

            if (afterMovingPlatform)
            {
                transform.parent = null;
                afterMovingPlatform = false;
            }
        }

        if ((coll.gameObject.tag == "Respawn" || coll.gameObject.tag == "Enemy") && (this.anim.GetCurrentAnimatorStateInfo(0).IsName("Attack Right") || this.anim.GetCurrentAnimatorStateInfo(0).IsName("Attack Left")))
        {
            EnemyHealth.giveDamage();
        }
        else if (coll.gameObject.tag == "Respawn" || coll.gameObject.tag == "Enemy")
        {
            CoinScore.score = 0;
            Health.health = 3;
            EnemyHealth.enemyHealth = 1;
            SceneManager.LoadScene("LevelF");
            Debug.Log("RESPAWN");
        }

        if (coll.gameObject.tag == "MovingPlatform")
        {
            onGround = true;
            afterMovingPlatform = true;
            transform.parent = coll.transform;
        }   
    }

    //void onCollisionExit2D(Collision2D coll)
    //{
    //    Debug.Log("EXIT");
    //    if (coll.gameObject.tag == "MovingPlatform")
    //    {
    //        transform.parent = null;
    //    }
    //}
}


脚本附加到敌人身上。他们都统一输入了敌人生命值:1。

using UnityEngine;
using System.Collections;

public class EnemyHealth : MonoBehaviour {

    public static int enemyHealth = 1;
    public Transform explosion;
    public int enemyHealths;
    CircleCollider2D coll;

    // Use this for initialization
    void Start () {
        coll = GetComponent<CircleCollider2D>();
    }

    // Update is called once per frame
    void Update()
    {
        enemyHealths = enemyHealth;
        if (enemyHealths <= 0)
        {
            Instantiate(explosion, transform.position, transform.rotation);
            Destroy(coll.gameObject);
        }
    }

    public static void giveDamage()
    {
        enemyHealth -= 1;
    }
}
c# unity-game-engine
1个回答
3
投票

仅仅因为函数

giveDamage
被声明为
static
(敌人健康成员也是如此)

使用static修饰符来声明静态成员,该成员属于类型本身而不是特定的对象。

因此,每个敌人都有相同的生命值,当你伤害一个敌人时,事实上,你伤害了所有敌人。

每个敌人都必须有自己的生命值。删除

static
关键字并在播放器脚本中执行以下操作

if ((coll.gameObject.tag == "Respawn" || coll.gameObject.tag == "Enemy") && (this.anim.GetCurrentAnimatorStateInfo(0).IsName("Attack Right") || this.anim.GetCurrentAnimatorStateInfo(0).IsName("Attack Left")))
{
    coll.gameObject.GetComponent<EnemyHealth>().giveDamage();
}
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