请求如何处理关系处理中的if命令

Question

请求如何处理

if

关系处理中的命令

你好，工匠，美好的一天，
拜托，我需要有关

if

命令不适用于关系的帮助。我想获得

hashCard

的正确关系，但只有默认关系有效。

if

语句不会检查

status

模型的

UserHashCard

字段，该模型使用枚举 (

'available', 'initiated', 'joined', 'completed'

)。

UserHashCard 模型代码

<?php
namespace App\Models;

use Illuminate\Database\Eloquent\Model;

class UserHashCard extends Model {
    protected $guarded = [];

    public function hashCard() {
        return $this->belongsTo(HashCard::class);
    }

    // Uncomment if needed
    // public function exchanges()
    // {
    //     return $this->hasMany(HashCardExchange::class, 'hash_card_id');
    // }

    public function initiatedExchanges()
    {
        return $this->hasMany(HashCardExchange::class, 'hash_card_id', 'hash_card_id');
    }

    public function joinedExchanges()
    {
        return $this->hasMany(HashCardExchange::class, 'hash_card_id', 'join_card_id');
    }

    public function exchanges()
    {
        if ($this->status == 'initiated') {
            return $this->initiatedExchanges();
        } elseif ($this->status == 'joined') {
            return $this->joinedExchanges();
        }

        // Default relationship (e.g., for 'available' or other statuses)
        return $this->initiatedExchanges();
    }
}

Controller Code
php
Copy code
public function getHashCards() {
    $user = User::find(Auth::user()->id);

    $hashCards = $this->allCards($user->id);

    return response()->json($hashCards);
}

private function allCards($userid)
{
    $user = User::find($userid);

    // Fetch UserHashCards with their exchanges and associated usernames
    $hashCards = UserHashCard::query()
        ->where('user_id', $user->id)
        ->with([
            'hashCard', // Existing relationship
            'exchanges' => function ($query) {
                $query->with(['user:id,username']); // Eager load only the `id` and `username` fields from `users`
            }
        ])
        ->orderByRaw("
            CASE 
                WHEN status = 'initiated' THEN 1
                WHEN status = 'joined' THEN 2
                ELSE 3
            END
        ")
        ->get();

    return $hashCards;
}

Answer 1

我前段时间也遇到过几乎同样的问题。我想获取具有活跃订单的用户，这就是它的工作原理：

public function getUsersWithActiveOrders() {
$users = User::with('orders')->get();
$users->transform(function ($user) {
    $user->active_orders = $user->orders->filter(function ($order) {
        return in_array($order->status, ['pending', 'shipped']);
    });
    return $user;
});
return response()->json($users);
}

就您而言，我认为您没有使用您定义的关系。应该是这样的：

public function conditionalExchanges() {
    if ($this->status == 'initiated') {
        return $this->initiatedExchanges;
    } elseif ($this->status == 'joined') {
        return $this->joinedExchanges;
    }
    return collect();
}

现在在您的控制器中，调用关系：

public function getHashCards() {
$user = User::find(Auth::user()->id);
$hashCards = $this->allCards($user->id);

$hashCards->each(function ($hashCard) {
    $hashCard->conditional_exchanges = $hashCard->conditionalExchanges();
});

return response()->json($hashCards);
}

对于 allCards 功能：

$hashCards = UserHashCard::query()
    ->where('user_id', $user->id)
    ->with('hashCard')
    ->orderByRaw("
        CASE 
            WHEN status = 'initiated' THEN 1
            WHEN status = 'joined' THEN 2
            ELSE 3
        END
    ")
    ->get();

如果此后有问题，请告诉我。