使用 Spring Boot 启动 JavaFX 2

问题描述 投票:0回答:2

我正在尝试使用 JavaFX 2 和 Spring Boot 创建新应用程序,但到目前为止,我的简单应用程序(如 hello world)尚未运行,因为

MainPaneController
中的“root is null”。

MainPaneController 类:

public class MainPaneController implements Initializable {

    public static final String VIEW = "/fxml/Scene.fxml";

    @FXML
    private Node root;

    @FXML
    private Label label;

    @PostConstruct
    public void init() {
    }

    public Node getRoot() {
        return root;
    }

    @FXML
    private void handleButtonAction(ActionEvent event) {
        System.out.println("You clicked me!");
        label.setText("Hello World!");
    }

    @Override
    public void initialize(URL url, ResourceBundle rb) {
        // TODO
    }

}

主类FxBootApplication:

@SpringBootApplication
public class FxBootApplication extends Application {

    private static String[] args;

    @Override
    public void start(final Stage stage) throws Exception {
        //Parent root = FXMLLoader.load(getClass().getResource("/fxml/Scene.fxml"));
        // Bootstrap Spring context here.
        ApplicationContext context = SpringApplication.run(FxBootApplication.class, args);

        MainPaneController mainPaneController = context.getBean(MainPaneController.class);

        Scene scene = new Scene((Parent) mainPaneController.getRoot()); // error here

        //Scene scene = new Scene(root);
        //scene.getStylesheets().add("/styles/Styles.css");
        stage.setTitle("JavaFX and Maven");
        stage.setScene(scene);
        stage.show();
    }

    /**
     * The main() method is ignored in correctly deployed JavaFX application.
     * main() serves only as fallback in case the application can not be
     * launched through deployment artifacts, e.g., in IDEs with limited FX
     * support. NetBeans ignores main().
     *
     * @param args the command line arguments
     */
    public static void main(String[] args) {
        FxBootApplication.args = args;
        launch(args);
    }

}

应用程序配置类:

@Configuration
public class ApplicationConfiguration {

    @Bean
    public MainPaneController mainPaneController() throws IOException {
        MainPaneController mpc = (MainPaneController) loadController(MainPaneController.VIEW);
        return mpc;
    }

    public <T> T loadController(String url) throws IOException {
        try (InputStream fxmlStream = getClass().getResourceAsStream(url)) {
            FXMLLoader loader = new FXMLLoader(getClass().getResource(url));
            //FXMLLoader.load(url);
            loader.load(fxmlStream);
            return loader.getController();
        }
    }

}

错误是当我尝试通过

controller.getRoot()
;

获取场景的根时

我遵循了这里提出的解决方案 -> JavaFX fxml - 如何使用带有嵌套自定义控件的 Spring DI? 但最终根本不适合我。 我应该先以某种方式初始化这个根吗?

java spring spring-boot javafx-2
2个回答
5
投票

不幸的是,我找不到对我有用的解决方案的链接...... 但是:我有代码,我对其进行了一定程度的测试。

首先你需要你的应用程序类:

package eu.dzim.yatafx;

import org.apache.logging.log4j.LogManager;
import org.apache.logging.log4j.Logger;
import org.springframework.beans.factory.annotation.Autowired;
import org.springframework.boot.CommandLineRunner;
import org.springframework.boot.SpringApplication;
import org.springframework.boot.autoconfigure.EnableAutoConfiguration;
import org.springframework.context.ConfigurableApplicationContext;
import org.springframework.context.annotation.ComponentScan;
import org.springframework.context.annotation.Configuration;

import eu.dzim.yatafx.model.app.ApplicationModel;
import eu.dzim.yatafx.spring.service.FXMLLoaderService;
import eu.dzim.yatafx.util.Utils;
import eu.dzim.yatafx.util.res.StringResource;
import javafx.application.Application;
import javafx.application.Platform;
import javafx.fxml.FXMLLoader;
import javafx.scene.Scene;
import javafx.scene.layout.Pane;
import javafx.stage.Stage;

@Configuration
@EnableAutoConfiguration
@ComponentScan
public class YataFXApplication extends Application implements CommandLineRunner {

    private static final Logger LOG = LogManager.getLogger(FileSyncFXApplication.class);

    @Override
    public void run(String... args) {
        // something to call prior to the real application starts?
    }

    private static String[] savedArgs;

    // locally stored Spring Boot application context
    private ConfigurableApplicationContext applicationContext;

    // we need to override the FX init process for Spring Boot
    @Override
    public void init() throws Exception {

        // set Thread name
        Thread.currentThread().setName("main");

        // LOG.debug("Init JavaFX application");
        applicationContext = SpringApplication.run(getClass(), savedArgs);
        applicationContext.getAutowireCapableBeanFactory().autowireBean(this);
    }

    // ... and close our context on stop of the FX part
    @Override
    public void stop() throws Exception {
        // LOG.debug("Stop JavaFX application");
        super.stop();
        applicationContext.close();
    }

    protected static void launchApp(Class<? extends FileSyncFXApplication> appClass, String[] args) {
        FileSyncFXApplication.savedArgs = args;
        Application.launch(appClass, args);
    }

    @Autowired
    private FXMLLoaderService mFXMLLoaderService;

    @Autowired
    private ApplicationModel mApplicationModel;

    @Override
    public void start(Stage primaryStage) {

        // set Thread name
        Thread.currentThread().setName("main-ui");

        try {
            FXMLLoader loader = mFXMLLoaderService.getLoader(Utils.getFXMLResource("Root"), StringResource.getResourceBundle());

            Pane root = loader.load();

            Scene scene = new Scene(root, 1200, 800);
            scene.getStylesheets().add("/eu/dzim/filesyncfx/ui/application.css");

            primaryStage.setScene(scene);
            primaryStage.setOnCloseRequest(windowEvent -> {

                LOG.debug("tear down JavaFX application");
                // mApplicationModel.setLoggedIn(!mLoginService.logout());

                // orderly shut down FX
                Platform.exit();

                // But: there might still be a daemon thread left over from OkHttp (some async dispatcher)
                // so assume everything is fine and call System.exit(0)
                System.exit(0);
            });

            primaryStage.show();

        } catch (Exception e) {
            LOG.error(e.getMessage(), e);
        }
    }

    public static void main(String[] args) throws Exception {

        // SpringApplication.run(SampleSimpleApplication.class, args);

        savedArgs = args;
        Application.launch(FileSyncFXApplication.class, args);
    }
}

我用

org.springframework.boot:spring-boot-starter-parent:1.3.3.RELEASE
作为基础。

注意我在此处自动连接的

FXMLLoaderService
接口:

package eu.dzim.yatafx.spring.service;

import java.net.URL;
import java.util.ResourceBundle;

import javafx.fxml.FXMLLoader;

public interface FXMLLoaderService {

    FXMLLoader getLoader();

    FXMLLoader getLoader(URL location);

    FXMLLoader getLoader(URL location, ResourceBundle resourceBundle);
}

实现如下所示:

package eu.dzim.yatafx.spring.service.impl;

import java.net.URL;
import java.util.ResourceBundle;

import javax.annotation.PostConstruct;
import javax.annotation.PreDestroy;

import org.apache.logging.log4j.LogManager;
import org.apache.logging.log4j.Logger;
import org.springframework.beans.factory.annotation.Autowired;
import org.springframework.context.ConfigurableApplicationContext;
import org.springframework.context.annotation.Scope;
import org.springframework.stereotype.Component;

import eu.dzim.yatafx.spring.service.FXMLLoaderService;
import javafx.fxml.FXMLLoader;
import javafx.util.Callback;

@Component
@Scope("singleton")
public class FXMLLoaderServiceImpl implements FXMLLoaderService {

    private static final Logger LOG = LogManager.getLogger(FXMLLoaderServiceImpl.class);

    @Autowired
    private ConfigurableApplicationContext context;

    @PostConstruct
    private void postConstruct() {
        LOG.debug("PostConstruct: set up " + getClass().getName());
    }

    @Override
    public FXMLLoader getLoader() {
        FXMLLoader loader = new FXMLLoader();
        loader.setControllerFactory(new Callback<Class<?>, Object>() {
            @Override
            public Object call(Class<?> param) {
                return context.getBean(param);
            }
        });
        return loader;
    }

    @Override
    public FXMLLoader getLoader(URL location) {
        FXMLLoader loader = new FXMLLoader(location);
        loader.setControllerFactory(new Callback<Class<?>, Object>() {
            @Override
            public Object call(Class<?> param) {
                return context.getBean(param);
            }
        });
        return loader;
    }

    @Override
    public FXMLLoader getLoader(URL location, ResourceBundle resourceBundle) {
        FXMLLoader loader = new FXMLLoader(location, resourceBundle);
        loader.setControllerFactory(new Callback<Class<?>, Object>() {
            @Override
            public Object call(Class<?> param) {
                return context.getBean(param);
            }
        });
        return loader;
    }

    @PreDestroy
    private void preDestroy() {
        LOG.debug("PreDestroy: tear down " + getClass().getName());
    }
}

用法已经显示在 Application 类中:只需 @Autowire 服务并从那里创建子视图。因为我几乎完全依赖 FXML,所以这个对我来说很重要,因为我想在我的控制器中使用所有这些不错的 DI 东西。

最好的例子是全局应用程序,它包含我附加到控制器类中的一些 JavaFX 属性。

虽然所示的应用程序更多的是一个存根(应用程序和 FXML 服务),但我有一个有趣的项目,我在并行开发的 Web 应用程序中使用了这种方法,该应用程序基于我在工作中开发的“微”服务进行 REST 处理.

希望代码足以作为示例,让它在您这边工作。如果您还有其他问题,请尽管询问。

干杯, 丹尼尔

编辑:我认为您代码中的错误只是FXML服务中的部分。我有这个注入的 ConfigurableApplicationContext,我用它来创建控制器。为此,您需要一个 ControllerFactory。


有一些第三方示例可协助 JavaFX 和 Spring Boot 集成:


0
投票

补充:这里有两个现成的模板,包含 JavaFX、Spring Boot 和 Maven/Gradle。

我将感谢 GitHub 上的明星支持它的免费开源,从而帮助您解决问题。 <3

https://github.com/davidweber411/javafx-JavaFxSpringBootGradleApp

https://github.com/davidweber411/javafx-JavaFxSpringBootMavenApp

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