如何在Python3中打印格式化的字符串？

Question

嘿，我有一个问题

print ("So, you're %r old, %r tall and %r heavy.") % (
    age, height, weight)

该行在python 3.4中不起作用。有人知道如何解决这个问题吗？

Answer 1

在Python 3.6中引入了f字符串。

你可以写这样的

print (f"So, you're {age} old, {height} tall and {weight} heavy.")

有关更多信息，请参阅：https://docs.python.org/3/whatsnew/3.6.html

Answer 2

您需要将格式应用于字符串，而不是print()函数的返回值：

print("So, you're %r old, %r tall and %r heavy." % (
    age, height, weight))

请注意)右括号的位置。如果它可以帮助您理解差异，请首先将格式化操作的结果分配给变量：

output = "So, you're %r old, %r tall and %r heavy." % (age, height, weight)
print(output)

Answer 3

你写：

print ("So, you're %r old, %r tall and %r heavy.") % (age, height, weight)

当正确的是：

print ("So, you're %r old, %r tall and %r heavy." % (age, height, weight))

除此之外，你应该考虑切换到“新”.format风格，它更加pythonic并且不需要声明类型声明。从Python 3.0开始，但向后移植到2.6+

print("So, you're {} old, {} tall and {} heavy.".format(age, height, weight))
#or for pinning(to skip the variable expanding if you want something 
#specific to appear twice for example)
print("So, you're {0} old, {1} tall and {2} heavy and {1} tall again".format(age, height, weight))

Answer 4

即使我不知道你得到了哪个例外，你也许可以尝试使用格式函数：

print ("So, you're {0} old, {1} tall and {2} heavy.".format(age, height, weight))

正如其他答案中所提到的，你的括号显然有些问题。

如果你想使用format，我仍然会把我的解决方案作为参考。

Answer 5

更简单的方法：

print ("So, you're ",age,"r old, ", height, " tall and ",weight," heavy." )

Answer 6

你的语法有问题，靠近

...) % (
    age, height, weight)

。

你已经在qazxsw poi运营商之前关闭了qazxsw poi。这就是为什么print函数不会携带你传递的参数。在你的代码中这样做，

%