雷达图-以变量为参考值

问题描述 投票:0回答:1

我正在构建一个雷达图图表,并且我有一些变量将返回数组作为雷达图中的值。但是,它不显示我的值。你能给些建议么?谢谢!

变量输出:

output of aa > array([0.38570075]
output of bb > array([0.37840411]
output of cc > array([0.23178026]
output of dd > array([0.00411487]
output of ee > 0

import plotly.graph_objects as go

categories = ['A', 'B', 'C', 'D', 'E']

fig = go.Figure()

fig.add_trace(go.Scatterpolar(
      r=[aa,bb,cc,dd,ee],
      theta=categories,
      fill='toself',
      name='Egress & Access'
))
fig.update_layout(
  polar=dict(
    radialaxis=dict(
      visible=True,
      range=[0, 1]
    )),
      showlegend=True
)

fig.show()
python plotly
1个回答
0
投票

问题是[aa, bb, cc, dd, ee]是一个数组列表而不是值列表。如果您按照下面的示例从数组中提取值,则代码应该可以工作。

import plotly.graph_objects as go
import numpy as np

aa = np.array([0.38570075])
bb = np.array([0.37840411])
cc = np.array([0.23178026])
dd = np.array([0.00411487])
ee = 0

categories = ['A', 'B', 'C', 'D', 'E']

fig = go.Figure()

fig.add_trace(go.Scatterpolar(
      r=[aa[0], bb[0], cc[0], dd[0], ee],
      theta=categories,
      fill='toself',
      name='Egress & Access'
))

fig.update_layout(
  polar=dict(
    radialaxis=dict(
      visible=True,
      range=[0, 1]
    )),
      showlegend=True
)

fig.show()
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