我基本上试图将 Unix 时间戳(time() 函数)转换为与过去和未来日期兼容的相对日期/时间。所以输出可能是:
2周前
1小时60分钟前
15分54秒前
10分15秒后
首先我尝试编写这个代码,但做了一个巨大的难以维护的功能,然后我在互联网上搜索了几个小时,但我所能找到的只是只产生一部分时间的脚本(例如:“1小时前”)没有会议记录)。
您有已经执行此操作的脚本吗?
此函数为您提供“1 小时前”或“明天”等“现在”和“特定时间戳”之间的结果。
function time2str($ts)
{
if(!ctype_digit($ts))
$ts = strtotime($ts);
$diff = time() - $ts;
if($diff == 0)
return 'now';
elseif($diff > 0)
{
$day_diff = floor($diff / 86400);
if($day_diff == 0)
{
if($diff < 60) return 'just now';
if($diff < 120) return '1 minute ago';
if($diff < 3600) return floor($diff / 60) . ' minutes ago';
if($diff < 7200) return '1 hour ago';
if($diff < 86400) return floor($diff / 3600) . ' hours ago';
}
if($day_diff == 1) return 'Yesterday';
if($day_diff < 7) return $day_diff . ' days ago';
if($day_diff < 31) return ceil($day_diff / 7) . ' weeks ago';
if($day_diff < 60) return 'last month';
return date('F Y', $ts);
}
else
{
$diff = abs($diff);
$day_diff = floor($diff / 86400);
if($day_diff == 0)
{
if($diff < 120) return 'in a minute';
if($diff < 3600) return 'in ' . floor($diff / 60) . ' minutes';
if($diff < 7200) return 'in an hour';
if($diff < 86400) return 'in ' . floor($diff / 3600) . ' hours';
}
if($day_diff == 1) return 'Tomorrow';
if($day_diff < 4) return date('l', $ts);
if($day_diff < 7 + (7 - date('w'))) return 'next week';
if(ceil($day_diff / 7) < 4) return 'in ' . ceil($day_diff / 7) . ' weeks';
if(date('n', $ts) == date('n') + 1) return 'next month';
return date('F Y', $ts);
}
}
function relativeTime($time) {
$d[0] = array(1,"second");
$d[1] = array(60,"minute");
$d[2] = array(3600,"hour");
$d[3] = array(86400,"day");
$d[4] = array(604800,"week");
$d[5] = array(2592000,"month");
$d[6] = array(31104000,"year");
$w = array();
$return = "";
$now = time();
$diff = ($now-$time);
$secondsLeft = $diff;
for($i=6;$i>-1;$i--)
{
$w[$i] = intval($secondsLeft/$d[$i][0]);
$secondsLeft -= ($w[$i]*$d[$i][0]);
if($w[$i]!=0)
{
$return.= abs($w[$i]) . " " . $d[$i][1] . (($w[$i]>1)?'s':'') ." ";
}
}
$return .= ($diff>0)?"ago":"left";
return $return;
}
用途:
echo relativeTime((time()-256));
4 minutes 16 seconds ago
这是我写的。显示相对于今天日期的过去日期。
/**
* @param $date integer of unixtimestamp format, not actual date type
* @return string
*/
function zdateRelative($date)
{
$now = time();
$diff = $now - $date;
if ($diff < 60){
return sprintf($diff > 1 ? '%s seconds ago' : 'a second ago', $diff);
}
$diff = floor($diff/60);
if ($diff < 60){
return sprintf($diff > 1 ? '%s minutes ago' : 'one minute ago', $diff);
}
$diff = floor($diff/60);
if ($diff < 24){
return sprintf($diff > 1 ? '%s hours ago' : 'an hour ago', $diff);
}
$diff = floor($diff/24);
if ($diff < 7){
return sprintf($diff > 1 ? '%s days ago' : 'yesterday', $diff);
}
if ($diff < 30)
{
$diff = floor($diff / 7);
return sprintf($diff > 1 ? '%s weeks ago' : 'one week ago', $diff);
}
$diff = floor($diff/30);
if ($diff < 12){
return sprintf($diff > 1 ? '%s months ago' : 'last month', $diff);
}
$diff = date('Y', $now) - date('Y', $date);
return sprintf($diff > 1 ? '%s years ago' : 'last year', $diff);
}
我喜欢 xdebug 的relativeTime 函数。问题是我需要它有一定的粒度。
换句话说,如果我决定,就在几秒钟或几分钟停止。 所以现在,
echo fTime(strtotime('-23 hours 5 minutes 55 seconds'),0);
会显示,
23 小时 5 分钟前
而不是
23小时5分55秒前
我还希望它在达到较高时间量之一时不要在数组中下降。 所以如果它显示年份,我只想显示年份和月份。 所以现在,
echo fTime(strtotime('-1 year 2 months 3 weeks 4 days 16 hours 15 minutes 22 seconds'),0);
会显示
1年零2个月前
而不是
1年2个月3周4天16小时15分22秒前
以下代码更改满足了我的需要。当然,Props 首先转到 xdebug。 希望其他人可能会发现它有用:
function fTime($time, $gran=-1) {
$d[0] = array(1,"second");
$d[1] = array(60,"minute");
$d[2] = array(3600,"hour");
$d[3] = array(86400,"day");
$d[4] = array(604800,"week");
$d[5] = array(2592000,"month");
$d[6] = array(31104000,"year");
$w = array();
$return = "";
$now = time();
$diff = ($now-$time);
$secondsLeft = $diff;
$stopat = 0;
for($i=6;$i>$gran;$i--)
{
$w[$i] = intval($secondsLeft/$d[$i][0]);
$secondsLeft -= ($w[$i]*$d[$i][0]);
if($w[$i]!=0)
{
$return.= abs($w[$i]) . " " . $d[$i][1] . (($w[$i]>1)?'s':'') ." ";
switch ($i) {
case 6: // shows years and months
if ($stopat==0) { $stopat=5; }
break;
case 5: // shows months and weeks
if ($stopat==0) { $stopat=4; }
break;
case 4: // shows weeks and days
if ($stopat==0) { $stopat=3; }
break;
case 3: // shows days and hours
if ($stopat==0) { $stopat=2; }
break;
case 2: // shows hours and minutes
if ($stopat==0) { $stopat=1; }
break;
case 1: // shows minutes and seconds if granularity is not set higher
break;
}
if ($i===$stopat) { break 0; }
}
}
$return .= ($diff>0)?"ago":"left";
return $return;
}
马库斯
这是我过去使用的:
function zdateRelative($date)
{
$diff = time() - $date;
$periods[] = [60, 1, '%s seconds ago', 'a second ago'];
$periods[] = [60*100, 60, '%s minutes ago', 'one minute ago'];
$periods[] = [3600*70, 3600, '%s hours ago', 'an hour ago'];
$periods[] = [3600*24*10, 3600*24, '%s days ago', 'yesterday'];
$periods[] = [3600*24*30, 3600*24*7, '%s weeks ago', 'one week ago'];
$periods[] = [3600*24*30*30, 3600*24*30, '%s months ago', 'last month'];
$periods[] = [INF, 3600*24*365, '%s years ago', 'last year'];
foreach ($periods as $period) {
if ($diff > $period[0]) continue;
$diff = floor($diff / $period[1]);
return sprintf($diff > 1 ? $period[2] : $period[3], $diff);
}
}
我需要一个给我如下结果的结果,所以我自己写了一个。希望这会对某人有所帮助。
使用示例:
$datetime = "2014-08-13 12:52:48";
echo getRelativeTime($datetime); //10 hours ago
echo getRelativeTime($datetime, 1); //10 hours ago
echo getRelativeTime($datetime, 2); //10 hours and 50 minutes ago
echo getRelativeTime($datetime, 3); //10 hours, 50 minutes and 50 seconds ago
echo getRelativeTime($datetime, 4); //10 hours, 50 minutes and 50 seconds ago
代码:
public function getRelativeTime($datetime, $depth=1) {
$units = array(
"year"=>31104000,
"month"=>2592000,
"week"=>604800,
"day"=>86400,
"hour"=>3600,
"minute"=>60,
"second"=>1
);
$plural = "s";
$conjugator = " and ";
$separator = ", ";
$suffix1 = " ago";
$suffix2 = " left";
$now = "now";
$empty = "";
# DO NOT EDIT BELOW
$timediff = time()-strtotime($datetime);
if ($timediff == 0) return $now;
if ($depth < 1) return $empty;
$max_depth = count($units);
$remainder = abs($timediff);
$output = "";
$count_depth = 0;
$fix_depth = true;
foreach ($units as $unit=>$value) {
if ($remainder>$value && $depth-->0) {
if ($fix_depth) {
$max_depth -= ++$count_depth;
if ($depth>=$max_depth) $depth=$max_depth;
$fix_depth = false;
}
$u = (int)($remainder/$value);
$remainder %= $value;
$pluralise = $u>1?$plural:$empty;
$separate = $remainder==0||$depth==0?$empty:
($depth==1?$conjugator:$separator);
$output .= "{$u} {$unit}{$pluralise}{$separate}";
}
$count_depth++;
}
return $output.($timediff<0?$suffix2:$suffix1);
}
你可以通过 packagist 使用 Carbon,太棒了:) https://github.com/briannesbitt/Carbon#api- humandiff
PHP 8.0.0 现在通过 IntlDateFormatter::format 添加了 IntlDateFormatter::RELATIVE_* 常量,对相对日期的实现相当弱。
在撰写本文时,这可能不是非常有用,因为它仅输出字符串“昨天”、“今天”和“明天”......然后它会回退到完整/长/中/短日期对于这些范围之外的任何事情。
其最大的吸引力在于它完全国际化;因此,使用其他语言环境(例如
de_DE
、ko_KR
或 pa_IN
)将为您提供相关脚本中翻译后的字符串...这可能是值得妥协的。
$formatter = new IntlDateFormatter(
'en_US',
IntlDateFormatter::RELATIVE_FULL,
IntlDateFormatter::NONE,
'America/Los_Angeles',
IntlDateFormatter::GREGORIAN
);
echo $formatter->format( time() - 86400 );
echo $formatter->format( time() );
echo $formatter->format( time() + 86400 );
未来的读者也有可能使用具有更全面的相对时间格式的较新版本的 PHP。
为什么不借鉴 drupal 的做法 - http://api.drupal.org/api/drupal/includes%21common.inc/function/format_interval/7
<?php
function format_interval($interval, $granularity = 2, $langcode = NULL) {
$units = array(
'1 year|@count years' => 31536000,
'1 month|@count months' => 2592000,
'1 week|@count weeks' => 604800,
'1 day|@count days' => 86400,
'1 hour|@count hours' => 3600,
'1 min|@count min' => 60,
'1 sec|@count sec' => 1,
);
$output = '';
foreach ($units as $key => $value) {
$key = explode('|', $key);
if ($interval >= $value) {
$output .= ($output ? ' ' : '') . format_plural(floor($interval / $value), $key[0], $key[1], array(), array('langcode' => $langcode));
$interval %= $value;
$granularity--;
}
if ($granularity == 0) {
break;
}
}
return $output ? $output : t('0 sec', array(), array('langcode' => $langcode));
}
?>
您可能不需要替换 t() 并且您可以很容易地为 format_plural 做自己的事情,因为您(可能)不必支持多种语言。 http://api.drupal.org/api/drupal/includes%21common.inc/function/format_plural/7
应该足够容易适应不同的格式。这个简单的函数仅适用于过去的时间戳。
// return relative date/time string from timestamp
// [n yrs] [n mos] [n days] h:i:s
function relative_time(int $time): string
{
$dt = new DateTime();
$dt->setTimestamp($time);
$diff = (new DateTime())->diff($dt);
$s = "";
if ($diff->y) $s .= " {$diff->y} " . (($diff->y > 1) ? "yrs" : "yr");
if ($diff->m) $s .= " {$diff->m} " . (($diff->m > 1) ? "mos" : "mo");
if ($diff->d) $s .= " {$diff->d} " . (($diff->d > 1) ? "days" : "day");
$s .= sprintf(" %02d:%02d:%02d", $diff->h, $diff->i, $diff->s);
return trim($s);
}