在PyQt5中使用QStackedWidget

问题描述 投票:0回答:1

我在ApplicationWindow类中有QStackedWidget,而按钮将指向MenuWindow中的不同QWidget。我在编写函数时需要帮助,该函数将根据单击的按钮更改CurrentWidget-例如login_button会将CurrentWidget更改为LoginWindow。当我自己尝试执行此操作时,由于刚开始学习Python,我遇到了递归问题。

from PyQt5.QtCore import *
from PyQt5.QtWidgets import *
import sys

class ApplicationWindow(QWidget):

def __init__(self):
    super(ApplicationWindow, self).__init__()
    # stack = Controller()
    self.menu = MenuWindow()
    self.login = LoginWindow()

    self.setGeometry(0, 0, 800, 600)
    self.setWindowTitle('Finance tracker')

    self.setAutoFillBackground(True)
    p = self.palette()
    p.setColor(self.backgroundRole(), Qt.green)
    self.setPalette(p)

    self.stack = QStackedWidget()
    self.stack.setSizePolicy(QSizePolicy.Maximum, QSizePolicy.Maximum)
    self.stack.addWidget(self.menu)
    self.stack.addWidget(self.login)
    self.stack.setCurrentWidget(self.menu)

    layout = QVBoxLayout()
    layout.addWidget(self.stack)
    layout.setAlignment(Qt.AlignCenter)
    self.setLayout(layout)

class MenuWindow(QWidget):

def __init__(self):
    super(MenuWindow, self).__init__()
    self.setGeometry(0, 0, 250, 200)
    box = QVBoxLayout()

    self.setAutoFillBackground(True)
    p = self.palette()
    p.setColor(self.backgroundRole(), Qt.red)
    self.setPalette(p)

    label = QLabel('Welcome to finance tracker')
    label.setStyleSheet('font: 24pt')
    box.addWidget(label, alignment=Qt.AlignCenter)

    login_button = QPushButton('Login')
    login_button.clicked.connect(qApp.exit)

    new_button = QPushButton('Create a new account')
    new_button.clicked.connect(qApp.exit)

    exit_button = QPushButton('Exit')
    exit_button.clicked.connect(qApp.exit)

    for button in [login_button, new_button, exit_button]:
        button.setStyleSheet('font: 14pt')
        button.setFixedSize(200, 50)
        box.addWidget(button, alignment=Qt.AlignCenter)

    self.setLayout(box)
    self.show()

class LoginWindow(QWidget):

def __init__(self):
    super(LoginWindow, self).__init__()
    self.setGeometry(0, 0, 10, 250)

    self.setAutoFillBackground(True)
    p = self.palette()
    p.setColor(self.backgroundRole(), Qt.blue)
    self.setPalette(p)

    label = QLabel('Welcome to finance tracker')
    box = QVBoxLayout()
    box.addWidget(label)
    self.setLayout(box)
    self.show()

if __name__ == '__main__':
    app = QApplication(sys.argv)
    window = ApplicationWindow()
    window.show()
    sys.exit(app.exec())
python pyqt qstackedwidget
1个回答
1
投票

由于您使用的是QPushButtons来切换页面,所以我会将它们添加到QButtonGroup中。这样,您可以将QButtonGroup.buttonClicked[int]信号连接到QStackedWidget.setCurrentIndex。在MenuWindow中保留一个指向QButtonGroup的指针。

class MenuWindow(QWidget):

    def __init__(self):
        ...
        login_button = QPushButton('Login')
        new_button = QPushButton('Create a new account')

        exit_button = QPushButton('Exit')
        exit_button.clicked.connect(qApp.exit)

        self.btn_group = QButtonGroup()
        for i, button in enumerate([login_button, new_button, exit_button]):
            button.setStyleSheet('font: 14pt')
            button.setFixedSize(200, 50)
            box.addWidget(button, alignment=Qt.AlignCenter)
            self.btn_group.addButton(button)
            self.btn_group.setId(button, i + 1)
        ...

现在您可以在ApplicationWindow中连接信号和插槽。

class ApplicationWindow(QWidget):

    def __init__(self):
        ...
        self.menu.btn_group.buttonClicked[int].connect(self.stack.setCurrentIndex)
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