我的原始数据集
df
bugid timestamp commenter Owner.
1 18348 2011-07-10 12:26:00 [email protected] No
2 18348 2011-07-11 10:47:16 ralf%[email protected] No
3 18348 2011-07-11 17:44:50 [email protected] Yes
4 18348 2011-07-11 18:13:17 [email protected] No
5 18348 2011-07-11 18:14:39 [email protected] No
6 18348 2011-07-11 18:23:54 [email protected] No
7 18348 2011-07-13 14:36:31 [email protected] No
8 18348 2011-07-15 18:16:12 [email protected] Yes
9 18348 2011-07-15 18:17:54 [email protected] Yes
10 18348 2011-07-26 06:35:04 [email protected] No
11 18348 2011-09-04 21:34:03 [email protected] No
12 18348 2011-09-13 23:14:20 [email protected] Yes
13 18348 2011-10-19 18:49:22 [email protected] No
dput（df）
structure(list(bugid = c(18348L, 18348L, 18348L, 18348L, 18348L,
18348L, 18348L, 18348L, 18348L, 18348L, 18348L, 18348L, 18348L
), timestamp = structure(1:13, .Label = c("2011-07-10 12:26:00",
"2011-07-11 10:47:16", "2011-07-11 17:44:50", "2011-07-11 18:13:17",
"2011-07-11 18:14:39", "2011-07-11 18:23:54", "2011-07-13 14:36:31",
"2011-07-15 18:16:12", "2011-07-15 18:17:54", "2011-07-26 06:35:04",
"2011-09-04 21:34:03", "2011-09-13 23:14:20", "2011-10-19 18:49:22"
), class = "factor"), commenter = structure(c(4L, 5L, 6L, 3L,
4L, 4L, 7L, 6L, 6L, 2L, 1L, 6L, 8L), .Label = c("[email protected]",
"[email protected]", "[email protected]", "[email protected]",
"ralf%[email protected]", "[email protected]", "[email protected]",
"[email protected]"), class = "factor"), Owner. = structure(c(1L,
1L, 2L, 1L, 1L, 1L, 1L, 2L, 2L, 1L, 1L, 2L, 1L), .Label = c("No",
"Yes"), class = "factor")), class = "data.frame", row.names = c(NA,
-13L))
然后执行以下操作：
df$date <- as.Date(df$timestamp)
数据集因此变为：
df
bugid timestamp commenter Owner. date
1 18348 2011-07-10 12:26:00 [email protected] No 2011-07-10
2 18348 2011-07-11 10:47:16 ralf%[email protected] No 2011-07-11
3 18348 2011-07-11 17:44:50 [email protected] Yes 2011-07-11
4 18348 2011-07-11 18:13:17 [email protected] No 2011-07-11
5 18348 2011-07-11 18:14:39 [email protected] No 2011-07-11
6 18348 2011-07-11 18:23:54 [email protected] No 2011-07-11
7 18348 2011-07-13 14:36:31 [email protected] No 2011-07-13
8 18348 2011-07-15 18:16:12 [email protected] Yes 2011-07-15
9 18348 2011-07-15 18:17:54 [email protected] Yes 2011-07-15
10 18348 2011-07-26 06:35:04 [email protected] No 2011-07-26
11 18348 2011-09-04 21:34:03 [email protected] No 2011-09-04
12 18348 2011-09-13 23:14:20 [email protected] Yes 2011-09-13
13 18348 2011-10-19 18:49:22 [email protected] No 2011-10-19
我删除了timestamp列，认为该列必定会引起问题：
remove.cols = names(df) %in% c("timestamp")
df.pruned <- df[!remove.cols]
但是，当我尝试使用以下方法生成时间轴时：
timelineS(df.pruned)
我收到错误：
Summary.factor（c（4L，5L，6L，3L，4L，4L，7L，6L，6L，2L，1L，：“分钟”对因素没有意义
在类似的问题上阅读主题后，尝试将日期字段转换为数字。但是似乎没有什么可以解决问题。请帮助。