计算之前和当前记录之间的差异

Question

如何计算当前记录与上一个记录之间的差异。

这是表格示例

| rid    | time                |    data |
|10000038| 2012-03-13 12:30:18 |     100 |
|10000052| 2012-03-13 12:30:18 |     120 |
|10000053| 2012-03-13 12:30:18 |     140 |
|10000038| 2012-03-13 12:20:18 |     160 |
|10000052| 2012-03-13 12:20:18 |     180 |
|10000053| 2012-03-13 12:20:18 |     160 |
|10000038| 2012-03-13 12:10:18 |     100 |
|10000052| 2012-03-13 12:10:18 |     160 |
|10000053| 2012-03-13 12:10:18 |     160 |

在这里我希望得到的结果是，

| rid    | time                |    data | DIf |
|10000038| 2012-03-13 12:30:18 |     100 | 0   |
|10000052| 2012-03-13 12:30:18 |     120 | 20  |
|10000053| 2012-03-13 12:30:18 |     140 | 20  |
|10000038| 2012-03-13 12:20:18 |     160 | 20  |
|10000052| 2012-03-13 12:20:18 |     180 | 20  |
|10000053| 2012-03-13 12:20:18 |     160 |-20  |
|10000038| 2012-03-13 12:10:18 |     100 |-60  |
|10000052| 2012-03-13 12:10:18 |     160 | 60  |
|10000053| 2012-03-13 12:10:18 |     160 | 0   |

注意：查看表，表中每次都会转储三个数据，并且具有单独的资源 id。如何找出差异？

Answer 1

您可以使用

LAG()

函数让您知道上一条记录的值。

就你而言，

lag(data, 1) over (order by time) as previou_val

会显示之前的数据！

Answer 2

确保表中有差异列。然后，每当您使用新值更新表时，请执行此操作

UPDATE 
   `tablename` 
SET 
    data = 120,
    diff = 120 -
    (
        SELECT prev_data
        FROM (
          SELECT data AS prev_data
          FROM tablename
          WHERE `id` = '1'
        )
       AS prev_data
    )
WHERE 
   id='1';

已测试且有效

演示

Answer 3

SELECT
    rid,
    `time`,
    data,
    data - (LAG(data, 1) OVER(ORDER BY `time` ASC)) AS DIf
FROM your_example_table;

Answer 4

您可以使用PHP， 当您循环遍历结果集时， 将值保存在临时变量中。 假设您获得的数据是整数，则使用它与下一行进行比较。

$previousRow = 0; //initiates value for preceeding row

while($row = mysql_fetch_assoc($result)){
   $currentRow = $row['data']; //gets current row
  //gets difference between the two variables
  $difference = $currentRow - $previousRow; 
  echo "\$difference = $difference<br>\n";
  $previousRow = $currentRow; //reassigns previous row
  //display otherfield
  //display $diff
 }