使用 openpyxl 将边框应用于范围内的所有单元格

Question

我有一个脚本，它采用 pandas 数据帧并将其分成数百块，并将每个块保存为单独的 Excel 文件。每个块将具有相同的列数，但行数不同。我已经弄清楚如何使用 openpyxl 将所有其他必要的格式应用于这些文件，但我尚未确定应用边框的最快方法。另外，我认为我只是没有正确应用边框，因为下面的代码（我怀疑不需要单独循环每个单元格）不应用任何边框。

from openpyxl.style import Border

wb = load_workbook(filename = _fname)
ws = wb.worksheets[0]  
for _row in ws.range('A1:L'+str(ws.get_highest_row() ) ):
    for _cell in _row:
            _cell.style.borders.left.border_style = Border.BORDER_THIN
            _cell.style.borders.right.border_style = Border.BORDER_THIN
            _cell.style.borders.top.border_style = Border.BORDER_THIN
            _cell.style.borders.bottom.border_style = Border.BORDER_THIN
wb.save(_fname)

所以这段代码有效，但它没有应用我期望的边框（Excel 中的默认边框），并且它需要的步骤比我想要的要多得多。我的期望是我应该能够做这样的事情：

from openpyxl.style import Border

wb = load_workbook(filename = _fname)
ws = wb.worksheets[0]

_range = ws.some_range_func('A1:L'+str(ws.get_highest_row() ) ):
    _range.style.borders.all_borders = Borders.BORDER_THIN

有这个功能吗？如果没有，有人可以请至少解释一下如何应用默认边框样式而不是这个稍厚的边框吗？ Border.BORDER_THICK、Border.BORDER_MEDIUM、Border.BORDER_THIN 或 Border.BORDER_HAIR 似乎都不正确。

谢谢！

Answer 1

对于 openpyxl==3.0.5 来说，以更 Pythonic 的方式：

from openpyxl.styles import Border, Side

def set_border(ws, cell_range):
    thin = Side(border_style="thin", color="000000")
    for row in ws[cell_range]:
        for cell in row:
            cell.border = Border(top=thin, left=thin, right=thin, bottom=thin)

set_border(worksheet, 'A5:C10') 

Answer 2

也许这很方便：

from openpyxl.reader.excel import load_workbook
from openpyxl.style import Border

def set_border(ws, cell_range):
    rows = was[cell_range]
    for row in rows:
        row[0].style.borders.left.border_style = Border.BORDER_THIN
        row[-1].style.borders.right.border_style = Border.BORDER_THIN
    for c in rows[0]:
        c.style.borders.top.border_style = Border.BORDER_THIN
    for c in rows[-1]:
        c.style.borders.bottom.border_style = Border.BORDER_THIN

#usage example:
ws = load_workbook('example.xlsx').get_active_sheet()
set_broder(ws, "C3:H10")

它的执行速度相当快。

Answer 3

@Karimov 的回答略有修改
下面是你的代码应该是这样的

from openpyxl.styles import Border, Side, Font, Alignment

def __format_ws__(self, ws, cell_range):
     border = Border(left=Side(border_style='thin', color='000000'),
                    right=Side(border_style='thin', color='000000'),
                    top=Side(border_style='thin', color='000000'),
                    bottom=Side(border_style='thin', color='000000'))

      rows = ws[cell_range]
      for row in rows:
          for cell in row:
              cell.border = border

使用列表理解的更快方法如下：

 def __format_ws__(self, ws, cell_range):

        #applying border and alignment
        font = Font(size=9)
        align=Alignment(horizontal='left', vertical='center')
        border = Border(left=Side(border_style='thin', color='000000'),
                        right=Side(border_style='thin', color='000000'),
                        top=Side(border_style='thin', color='000000'),
                        bottom=Side(border_style='thin', color='000000'))

        rows = [rows for rows in ws[cell_range]]
        flattened = [item for sublist in rows for item in sublist]
        [(setattr(cell,'border',border), setattr(cell,'font',font), setattr(cell,'alignment',align)) for cell in flattened]

使用方法是：

self.__format_ws__(ws=writer.book.worksheets[0], cell_range='A1:G10')

Answer 4

适用于 openpyxl 2.3.5 的决定

from openpyxl.styles import Border, Side

def set_border(ws, cell_range):
    border = Border(left=Side(border_style='thin', color='000000'),
                right=Side(border_style='thin', color='000000'),
                top=Side(border_style='thin', color='000000'),
                bottom=Side(border_style='thin', color='000000'))

    rows = ws.iter_rows(cell_range)
    for row in rows:
        for cell in row:
            cell.border = border

set_border(worksheet, 'A5:C10')

Answer 5

@user698585 你的方法看起来不错，但它不再有效，因为当前版本的 openpyxl 改变了实现。所以这应该更新为例如

    ws.cell(row=1, column=1).style.border.top.border_style = borders.BORDER_MEDIUM

但是会出现不允许更改样式的错误。 作为一种解决方法，我刚刚定义了专用样式，但它们只是当前样式加上边框定义的重复 - 不是很好的解决方案，只有当您知道更改下的单元格是什么样式时才有效。

    border_style = Style(font=Font(name='Console', size=10, bold=False,
                         color=Color(openpyxl.styles.colors.BLACK)),
                         fill=PatternFill(patternType='solid', fgColor=Color(rgb='00C5D9F1')),
                         border=Border(bottom=Side(border_style='medium', color=Color(rgb='FF000000'))))

Answer 6

from copy import copy 

def set_border(ws, cell_range, style='thin'):
    rows = ws[cell_range]
    for row in rows:
        temp_row = copy(row[0].border)
        row[0].border = Border(left=Side(style=style), right=temp_row.right, top=temp_row.top, bottom=temp_row.bottom)

        temp_row = copy(row[-1].border)
        row[-1].border = Border(right=Side(style=style), left=temp_row.left, top=temp_row.top, bottom=temp_row.bottom)
    for c in rows[0]:
        temp_row = copy(c.border)
        c.border = Border(top=Side(style=style), left=temp_row.left, bottom=temp_row.bottom, right=temp_row.right)
    for c in rows[-1]:
        temp_row = copy(c.border)
        c.border = Border(bottom=Side(style=style), left=temp_row.left, top=temp_row.top, right=temp_row.right)

这会保留侧面的现有边框，您还可以设置边框的样式

Answer 7

如果您需要 pandas excel 数据框的样式（边框...），我的 fork 刚刚合并到 master 中 https://github.com/pydata/pandas/pull/2370#issuecomment-10898427

至于你的边界问题。 一次设置所有边框在 openpyxl 中不起作用。

In [34]: c.style.borders.all_borders.border_style = openpyxl.style.Border.BORDER_THIN

In [36]: c.style
'Calibri':11:False:False:False:False:'none':False:'FF000000':'none':0:'FFFFFFFF':'FF000000':'none':'FF000000':'none':'FF000000':'none':'FF000000':'none':'FF000000':'none':'FF000000':0:'thin':'FF000000':'none':'FF000000':'none':'FF000000':'none':'FF000000':'none':'FF000000':'general':'bottom':0:False:False:0:'General':0:'inherit':'inherit'

单独设置有效（'thin':'FF000000'）

In [37]: c.style.borders.top.border_style = openpyxl.style.Border.BORDER_THIN

In [38]: c.style
Out[38]: 'Calibri':11:False:False:False:False:'none':False:'FF000000':'none':0:'FFFFFFFF':'FF000000':'none':'FF000000':'none':'FF000000':'thin':'FF000000':'none':'FF000000':'none':'FF000000':0:'thin':'FF000000':'none':'FF000000':'none':'FF000000':'none':'FF000000':'none':'FF000000':'general':'bottom':0:False:False:0:'General':0:'inherit':'inherit'

可能是 openpyxl 中的一个错误。但没什么大不了的，只需在函数中设置底部，顶部，左侧，右侧即可

Answer 8

有同样的问题，但由于折旧，2019 年找不到任何解决此问题的方法。我有一些可以在下面工作的东西..可能会更好，但适用于所有意图和目的。

def set_border(ws, cell_range):
    rows = ws[cell_range]
    for row in rows:
        if row == rows[0][0] or row == rows[0][-1] or row == rows[-1][0] or row == rows[-1][-1]:
            pass
        else:
            row[0].border = Border(left=Side(style='thin'))
            row[-1].border = Border(right=Side(style='thin'))
        for c in rows[0]:
            c.border = Border(top=Side(style='thin'))
        for c in rows[-1]:
            c.border = Border(bottom=Side(style='thin'))
    rows[0][0].border = Border(left=Side(style='thin'), top=Side(style='thin'))
    rows[0][-1].border = Border(right=Side(style='thin'), top=Side(style='thin'))
    rows[-1][0].border = Border(left=Side(style='thin'), bottom=Side(style='thin'))
    rows[-1][-1].border = Border(right=Side(style='thin'), bottom=Side(style='thin'))

Answer 9

似乎没有内置的任务，我们必须自己做一些步骤，比如：

#need make conversion from alphabet to number due to range function
def A2N(s,e):
    return range(ord(s), ord(e)+1)
#B1 is the border you defined
#Assume you trying border A1-Q1 ... A3-Q3
X = A2N('A','Q')
#print X    
your_desired_sheet_range_rows = range(1,4)
#need two loop to go through cells
for row in your_desired_sheet_rows:
    for col in X:
        ca = chr(col)
        sheet[ca+str(row)].border=B1