python3 urllib3 PoolManager.requests 给出了意外的关键字“json”

Question

我正在 AWS 中使用 python3、urllib3 和 PoolManager.request() 构建 Lambda

我的代码：

def process_message(token, message):
    try:
        bucket_name = message['s3']['bucket']['name']
        object_name = message['s3']['object']['key']
        print(f"|---> Processing message {bucket_name}: {object_name}")
        # build request json
        req_json = { 'Bucket': bucket_name, 'Object': object_name }
        http = urllib3.PoolManager()
        bearer_token = "Bearer " + token
        auth_hdr = {'Authorization': bearer_token }
        ct_hdr = {'Content-Type': 'application/json'}
        obj_request_headers = {**auth_hdr, **ct_hdr}

        new_object_response = http.request('POST', oracle_notifier_listener_url, json = req_json, headers = obj_request_headers)
        logger.debug("Got new_object response: %s", new_object_response)

    except Exception as err:
        print("*---> An error occurred processing new object notification")
        raise err

我收到错误：

{
  "errorMessage": "HTTPResponse.__init__() got an unexpected keyword argument 'json'",
  "errorType": "TypeError",
  "requestId": "8d6c5511-6ca6-4245-8042-3aa5b3b98f89",
  "stackTrace": [
    "  File \"/var/task/lambda_function.py\", line 23, in lambda_handler\n        process_message(token, message)\n",
    "  File \"/var/task/lambda_function.py\", line 107, in process_message\n    raise err\n",
    "  File \"/var/task/lambda_function.py\", line 102, in process_message\n        new_object_response = http.request('POST', oracle_notifier_listener_url, json = req_json, headers = obj_request_headers)\n",

奇怪的是，请求似乎处理得很好，我可以在日志中看到 202 响应状态：

[DEBUG] 2024-10-15T17:05:11.150Z    8d6c5511-6ca6-4245-8042-3aa5b3b98f89    Starting new HTTPS connection (1): endpt.com:443
[DEBUG] 2024-10-15T17:05:12.375Z    8d6c5511-6ca6-4245-8042-3aa5b3b98f89    https://endpt:443 "POST /path/to/getObject HTTP/1.1" 202 None

我也尝试过：

    new_object_response = http.request('POST', oracle_notifier_listener_url, json = json.dumps(req_json), headers = obj_request_headers)

我得到了相同的响应，相同的错误。

FWIW，我正在使用这些文档：https://urllib3.readthedocs.io/en/stable/reference/urllib3.poolmanager.html

全世界伟大的 Python 开发者，我做错了什么？

Answer 1

此错误表明您的 urllib3 版本太旧 (1.x)。

json

关键字参数是

urllib3

v2 中的新参数。升级urllib3.