Valgrind:libmysql示例程序给出“仍然可达:”泄漏

问题描述 投票:1回答:2

我在项目中使用libmysql,每次在Valgrind中,每次都能看到确切的泄漏摘要“仍然可以到达:73,944字节,共21个块”,这不应该存在。后来我从[link

测试了此示例程序
/* Simple C program that connects to MySQL Database server*/
#include <mysql.h>
#include <stdio.h>
main() {
   MYSQL *conn;
   MYSQL_RES *res;
   MYSQL_ROW row;
   char *server = "localhost";
   char *user = "root";
   char *password = "PASSWORD"; /* set me first */
   char *database = "mysql";
   conn = mysql_init(NULL);
   /* Connect to database */
   if (!mysql_real_connect(conn, server,
         user, password, database, 0, NULL, 0)) {
      fprintf(stderr, "%s\n", mysql_error(conn));
      exit(1);
   }
   /* send SQL query */
   if (mysql_query(conn, "show tables")) {
      fprintf(stderr, "%s\n", mysql_error(conn));
      exit(1);
   }
   res = mysql_use_result(conn);
   /* output table name */
   printf("MySQL Tables in mysql database:\n");
   while ((row = mysql_fetch_row(res)) != NULL)
      printf("%s \n", row[0]);
   /* close connection */
   mysql_free_result(res);
   mysql_close(conn);
}

当我与Valgrind一起运行时,我仍然得到:

==22556== LEAK SUMMARY:
==22556==    definitely lost: 0 bytes in 0 blocks
==22556==    indirectly lost: 0 bytes in 0 blocks
==22556==      possibly lost: 0 bytes in 0 blocks
==22556==    still reachable: 73,944 bytes in 21 blocks
==22556==         suppressed: 0 bytes in 0 blocks
  1. 这是否令人担心?
  2. 这是libmysql中的错误吗?
c valgrind libmysql
2个回答
1
投票

“仍可访问”并不表示存在问题。从horse's mouth

“仍可访问”表示您的程序可能还不错-它不是免费的它可能有一些记忆。这是很常见的且通常是合理的。如果您不想看到这些报告,请不要使用--show-reachable = yes。


0
投票

之后

mysql_close(conn);

电话:

mysql_library_end()

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