我正在尝试使用一个不会返回到第一个位置的关键帧,我的意思是如果我从左到右转换,保持右转不返回到左侧。
码
div {
width: 100px;
height: 100px;
background-color: red;
position: relative;
-webkit-animation-name: example;
-webkit-animation-duration: 4s;
animation-name: example;
animation-duration: 4s;
}
/* Safari 4.0 - 8.0 */
@-webkit-keyframes example {
0% {
background-color: red;
left: 0px;
top: 0px;
}
100% {
background-color: yellow;
left: 200px;
top: 0px;
}
}
/* Standard syntax */
@keyframes example {
0% {
background-color: red;
left: 0px;
top: 0px;
}
100% {
background-color: yellow;
left: 200px;
top: 0px;
}
}
<div></div>
你只需要将animation-fill-mode: forwards;
添加到div中。
div {
width: 100px;
height: 100px;
background-color: red;
position: relative;
-webkit-animation-name: example;
-webkit-animation-duration: 4s;
-webkit-animation-fill-mode: forwards;
animation-name: example;
animation-duration: 4s;
animation-fill-mode: forwards;
}
/* Safari 4.0 - 8.0 */
@-webkit-keyframes example {
0% {background-color:red; left:0px; top:0px;}
100% {background-color:yellow; left:200px; top:0px;}
}
/* Standard syntax */
@keyframes example {
0% {background-color:red; left:0px; top:0px;}
100% {background-color:yellow; left:200px; top:0px;}
}
<div></div>
你只需要添加'animation-iteration-count:1'就可以单次运行,或者如果你想在循环中使用它,那么可以在div中尝试'animation-iteration-count:infinite'。
div {
width: 100px;
height: 100px;
background-color: red;
position: relative;
-webkit-animation-name: example;
-webkit-animation-duration: 4s;
animation-name: example;
animation-duration: 4s;
animation-iteration-count: 1; /*value can be infinite if you want to it in loop */
}
/* Safari 4.0 - 8.0 */
@-webkit-keyframes example {
0% {
background-color: red;
left: 0px;
top: 0px;
}
50%{
background-color: yellow;
left: 200px;
top: 0px;
}
100% {
background-color: red;
left: 0px;
top: 0px;
}
}
/* Standard syntax */
@keyframes example {
0% {
background-color: red;
left: 0px;
top: 0px;
}
50%{
background-color: yellow;
left: 200px;
top: 0px;
}
100% {
background-color: red;
left: 0px;
top: 0px;
}
}
<div></div>