Python Key Error=0 - 在代码中找不到 Dict 错误

问题描述 投票:0回答:5

基本上,我已经绞尽脑汁想知道为什么我的代码不起作用,我已经单独测试了各个部分,并在整个网络上查找它是否有帮助,但无济于事。 我收到一个错误,回溯是:

Traceback (most recent call last):
File "yes2.py", line 62, in <module>
g.add_edge(row_index,col_index, b)
File "yes2.py", line 27, in add_edge
self.adj[u].append(edge) 
KeyError: 0

有错误的两部分是

    def add_edge(self, u, v, w=0): 
    if u == v: 
        raise ValueError("u == v") 
    edge = Edge(u,v,w) 
    redge = Edge(v,u,0) 
    edge.redge = redge 
    redge.redge = edge 
    self.adj[u].append(edge) #### LINE 27 ####
    self.adj[v].append(redge) 
    self.flow[edge] = 0 
    self.flow[redge] = 0 

g = FlowNetwork()
map(g.add_vertex, ['0','1','2','3','4','5','6'])
with open('network.txt', "r") as file:
for row_index, row in enumerate(file):
    for col_index, value in enumerate(row.split(",")):
        b = int(value)
        if b != 0:
            g.add_edge(row_index,col_index, b) ### LINE 62 ####

这是完成的代码,因为没有这个代码可能很难看到发生了什么

class Edge(object):
def __init__(self, u, v, w):
    self.source = u
    self.sink = v 
    self.capacity = w 
def __repr__(self): 
    return "%s->%s:%s" % (self.source, self.sink, self.capacity) 

class FlowNetwork(object): 
def __init__(self): 
    self.adj = {} 
    self.flow = {} 

def add_vertex(self, vertex): 
    self.adj[vertex] = [] 

def get_edges(self, v): 
    return self.adj[v] 

def add_edge(self, u, v, w=0): 
    if u == v: 
        raise ValueError("u == v") 
    edge = Edge(u,v,w) 
    redge = Edge(v,u,0) 
    edge.redge = redge 
    redge.redge = edge 
    self.adj[u].append(edge) 
    self.adj[v].append(redge) 
    self.flow[edge] = 0 
    self.flow[redge] = 0 

def find_path(self, source, sink, path): 
    if source == sink: 
        return path 
    for edge in self.get_edges(source): 
        residual = edge.capacity - self.flow[edge] 
        if residual > 0 and not (edge,residual) in path: 
            result = self.find_path( edge.sink, sink, path + [(edge,residual)] ) 
            if result != None: 
                return result 

def max_flow(self, source, sink): 
    path = self.find_path(source, sink, []) 
    while path != None: 
        flow = min(res for edge,res in path) 
        for edge,res in path: 
            self.flow[edge] += flow 
            self.flow[edge.redge] -= flow 
        path = self.find_path(source, sink, []) 
    return sum(self.flow[edge] for edge in self.get_edges(source)) 

g = FlowNetwork()
map(g.add_vertex, ['0','1','2','3','4','5','6'])
with open('network.txt', "r") as file:
# enumerate allows you to iterate through the list with an index and an object
for row_index, row in enumerate(file):
    # split allows you to break a string apart with a string key
    for col_index, value in enumerate(row.split(",")):
        #convert value from string to int
        b = int(value)
        if b != 0:
            g.add_edge(row_index,col_index, b)

print g.max_flow('1','6')

非常感谢您抽出时间,非常感谢。

python keyerror
5个回答
24
投票

您收到的错误是

self.adj
还没有密钥
0
。您正在尝试追加到尚不存在的列表。

考虑使用

defaultdict
代替,替换此行(在
__init__
中):

self.adj = {}

这样:

self.adj = defaultdict(list)

您需要在顶部导入:

from collections import defaultdict

现在,

KeyError
不再提出
self.adj[0].append(edge)
,而是自动创建一个列表以追加到其中。


7
投票

defaultdict 解决方案更好。 但为了完整起见,您还可以在追加之前检查并创建空列表。 添加 + 行:

+ if not u in self.adj.keys():
+     self.adj[u] = []
  self.adj[u].append(edge)
.
.

3
投票

仅当您的列表或词典在本地功能中不可用时才会出现。


0
投票

试试这个:

class Flonetwork(Object):
    def __init__(self,adj = {},flow={}):
        self.adj = adj
        self.flow = flow

0
投票

当您尚未为键定义任何值并尝试使用

+=
运算符向其附加新值时,会发生此错误。例如。

s = "PA"
dict = {}
r = 0
for i in s:
    dict[r] += i

这将导致 KeyError,因为我还没有为 Key 定义任何值

dict[r]

但是如果你写一段代码:

for j in range(len(s)):
    dict[j] = ''

那么你将不会得到 KeyErrors,因为你已经将 dict 定义为:

{0: '', 1: ''}

希望这有帮助!

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