如何在长按后检测按钮的释放？

Question

想要释放按钮，已经实现了onLongClick()和onClick()侦听器，它们工作正常，但是如何检测Release。实际上想要创建一个类似于WhatsApp音频录制按钮的按钮，如果短按或触摸没有任何作用，则长时间按住会开始录制音频，并在释放[[stops录制时。

听众

            @Override
            public void onClick(View v) {
                shortClick();
            }
        });

       btn.setOnLongClickListener(new View.OnLongClickListener() {
           @Override
           public boolean onLongClick(View v) {
               longClick();
               return true;
           }
       });

功能

 public void shortClick()
    {
        Toast.makeText(this, "Short click Cancel !!!", Toast.LENGTH_SHORT).show();

    }

    public void longClick()
    {
        Toast.makeText(this, "Long click started - Recording started !!!", Toast.LENGTH_SHORT).show();

    }

因此，需要释放功能。

Answer 1

这是工作代码

@Override
public boolean dispatchKeyEvent(KeyEvent KEvent) 
{
    int keyaction = KEvent.getAction();

    if(keyaction == KeyEvent.ACTION_DOWN)
    {
        int keycode = KEvent.getKeyCode();
        int keyunicode = KEvent.getUnicodeChar(KEvent.getMetaState() );
        char character = (char) keyunicode;

        System.out.println("DEBUG MESSAGE KEY=" + character + " KEYCODE=" +  keycode);
    }


    return super.dispatchKeyEvent(KEvent);
}