“无法推断复杂的闭包返回类型;添加显式类型以消除歧义” SwiftUI中的错误

问题描述 投票:0回答:1

我正在尝试制作秒表应用程序。

代码:

import SwiftUI

struct StopWatchButton : View {
    var actions: [() -> Void]
    var labels: [String]
    var color: Color
    var isPaused: Bool

    var body: some View {
        let buttonWidth = (UIScreen.main.bounds.size.width / 2) - 12

        return Button(action: {
            if self.isPaused {
                self.actions[0]()
            } else {
                self.actions[1]()
            }
        }) {
            if isPaused {
                Text(self.labels[0])
                    .foregroundColor(.white)
                    .frame(width: buttonWidth,
                           height: 50)
            } else {
                Text(self.labels[1])
                    .foregroundColor(.white)
                    .frame(width: buttonWidth,
                           height: 50)
            }
        }
        .background(self.color)
    }
}

struct ContentView : View {
    @ObservedObject var stopWatch = StopWatch()

    var body: some View {
        VStack {
            Text(self.stopWatch.stopWatchTime)
                .font(.custom("courier", size: 70))
                .frame(width: UIScreen.main.bounds.size.width,
                       height: 300,
                       alignment: .center)

            HStack{
                StopWatchButton(actions: [self.stopWatch.reset, self.stopWatch.lap],
                                labels: ["Reset", "Lap"],
                                color: Color.red,
                                isPaused: self.stopWatch.isPaused())

                StopWatchButton(actions: [self.stopWatch.start, self.stopWatch.pause],
                                labels: ["Start", "Pause"],
                                color: Color.blue,
                                isPaused: self.stopWatch.isPaused())
            }

            VStack(alignment: .leading) {
                Text("Laps")
                    .font(.title)
                    .padding()

                List {
                    ForEach(self.stopWatch.laps.identified(by: \.uuid)) { (LapItem) in
                        Text(LapItem.stringTime)
                    }
                }
            }
        }
    }
}

StopWatch.swift视图文件来自here

我得到“无法推断复杂的闭包返回类型;添加显式类型以消除歧义”]中的错误>

struct ContentView : View {
    @ObservedObject var stopWatch = StopWatch()

    var body: some View {
        VStack {
            Text(self.stopWatch.stopWatchTime)
                .font(.custom("courier", size: 70))

在“ VStack {”行中的一部分

Code Error

我仅在添加了最后一个VStack部分后才收到此错误:

VStack(alignment: .leading) {
                Text("Laps")
                    .font(.title)
                    .padding()

                List {
                    ForEach(self.stopWatch.laps.identified(by: \.uuid)) { (LapItem) in
                        Text(LapItem.stringTime)
                    }
                }
            }

[我怀疑可能是由于列表的缘故,我什至尝试在多个位置添加Group {},但它无济于事,也无法在StopWatch.swift file中找到任何修正。我是Swift和Xcode的新手。为什么会发生这种情况,我该如何解决?

我正在尝试制作秒表应用。代码:import SwiftUI struct StopWatchButton:查看{var操作:[()->无效] var标签:[String] var颜色:Color var isPaused:Bool ...

ios swift xcode swiftui stopwatch
1个回答
0
投票

我能够通过添加id字段来进行编译。

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