我正在努力获得一名员工的工资,我不确定ISNULL为什么不在这里工作。虽然在子查询外使用时相同的查询也可以工作。也许我正在实现Isnull功能错误。即使有基本工资,净工资也显示为零。
DECLARE @dateFrom datetime
SET @dateFrom = '2018-03-01'
DECLARE @dateTo datetime
SET @dateTo = '2018-03-31'
Select
[Emp].ID
,[Emp].EmpCode
,[Emp].FirstName + ' ' + [Emp].LastName AS Name
,[Emp].BasicPay
,((select SUM(InstallmentAmount) from HRM.tbl_EmployeeLoanInstallment [Loan]
LEFT JOIN HRM.tbl_EmployeeLoan [EmpLoan] ON [EmpLoan].ID = [Loan].EmployeeLoanCode
where [EmpLoan].EmpCode = Emp.ID AND IsReceived != 1
AND CONVERT(date, [Loan].InstallmentDueOn) >= CONVERT(date, @dateFrom)
AND CONVERT(date, [Loan].InstallmentDueOn) <= CONVERT(date, @dateTo))) AS LoanDeduction
,( SELECT
(ISNULL([Info].[BasicPay], 0))
-
(SELECT SUM(ISNULL([Loan].InstallmentAmount, 0))
FROM [HRM].[tbl_EmployeeLoan] [EmpLoan]
FULL JOIN [HRM].[tbl_EmployeeInfo] [Info] ON [Info].[ID] = [EmpLoan].[EmpCode]
FULL JOIN [HRM].[tbl_EmployeeLoanInstallment] [Loan] ON [EmpLoan].[ID] = [Loan].[EmployeeLoanCode]
WHERE
CONVERT(date, [Loan].InstallmentDueOn) >= CONVERT(date, @dateFrom)
AND
CONVERT(date, [Loan].InstallmentDueOn) <= CONVERT(date, @dateTo)
AND
[Info].[ID] = [Emp].[ID]
GROUP BY Info.ID)
FROM
[HRM].[tbl_EmployeeInfo] [Info]
WHERE Info.ID = Emp.ID
GROUP BY [Info].[ID], [Info].[BasicPay]
) AS NetSalary
from HRM.tbl_EmployeeInfo [Emp]
输出:
412 C3-345 Ayesha Fatima 20000.00 NULL NULL
413 C3-651 Zainab Ali 20000.00 NULL NULL
414 C1343 Ahmed Abdullah 20000.00 11111.11 8888.89
415 231 Ahmed Aslam 20000.00 NULL NULL
416 FS-16 Fawaz Aslam 25000.00 NULL NULL
您确定子查询返回值吗?似乎并非如此。如果你真的想要一个值,你应该在子查询的末尾捕获你的空值。
,ISNULL(
( SELECT
(ISNULL([Info].[BasicPay], 0))
-
(SELECT SUM(ISNULL([Loan].InstallmentAmount, 0))
FROM [HRM].[tbl_EmployeeLoan] [EmpLoan]
FULL JOIN [HRM].[tbl_EmployeeInfo] [Info] ON [Info].[ID] = [EmpLoan].[EmpCode]
FULL JOIN [HRM].[tbl_EmployeeLoanInstallment] [Loan] ON [EmpLoan].[ID] = [Loan].[EmployeeLoanCode]
WHERE
CONVERT(date, [Loan].InstallmentDueOn) >= CONVERT(date, @dateFrom)
AND
CONVERT(date, [Loan].InstallmentDueOn) <= CONVERT(date, @dateTo)
AND
[Info].[ID] = [Emp].[ID]
GROUP BY Info.ID)
, 0)
FROM
[HRM].[tbl_EmployeeInfo] [Info]