PHP：DomElement-> getAttribute

Question

如何获取元素的所有属性？就像下面的示例一样，我一次只能获得一个，我想拉出所有anchor标签的属性。

$dom = new DOMDocument();
@$dom->loadHTML(http://www.example.com);

$a = $dom->getElementsByTagName("a");
echo $a->getAttribute('href');

谢谢！

Answer 1

“灵感来自西蒙的答案。我认为您可以取消getAttribute调用，因此这是一个没有它的解决方案：

$attrs = array();
for ($i = 0; $i < $a->attributes->length; ++$i) {
  $node = $a->attributes->item($i);
  $attrs[$node->nodeName] = $node->nodeValue;
}
var_dump($attrs);

Answer 2

$length = $a->attributes->length;
$attrs = array();
for ($i = 0; $i < $length; ++$i) {
    $name = $a->attributes->item($i)->name;
    $value = $a->getAttribute($name);

    $attrs[$name] = $value;
}


print_r($attrs);

Answer 3

$a = $dom->getElementsByTagName("a");
foreach($a as $element)
{
   echo $element->getAttribute('href');
}

Answer 4

$html = $data['html'];
if(!empty($html)){
   $doc = new DOMDocument();
   $doc->loadHTML($html);
   $doc->saveHTML();
   $datadom = $doc->getElementsByTagName("input");
   foreach($datadom as $element)
   {
       $class =$class." ".$element->getAttribute('class');
   }
}