如何使用bcrypt使用Python Flask-Security加密密码？

Question

我试图在Flask-Security的文档中使用标准的基本示例，并使其工作，除了密码存储在纯文本中。

我知道这一行：

user_datastore.create_user(email='[email protected]', password='password')

我可以改为：

user_datastore.create_user(email='[email protected]', password=bcrypt.hashpw('password', bcrypt.gensalt()))

但是我认为Flask-Security负责（双？）盐渍加密，如果我添加app.config ['SECURITY_REGISTERABLE'] = True并转到/注册数据库，这次IS加密正确。

我知道我错过了一些简单但不太明白的地方..

from flask import Flask, render_template
from flask_sqlalchemy import SQLAlchemy
from flask_security import Security, SQLAlchemyUserDatastore, UserMixin, RoleMixin, login_required
import bcrypt

# Create app
app = Flask(__name__)
app.config['DEBUG'] = True
app.config['SQLALCHEMY_TRACK_MODIFICATIONS'] = False
app.config['SECRET_KEY'] = 'super-secret'
app.config['SQLALCHEMY_DATABASE_URI'] = 'sqlite:///login.db'
app.config['SECURITY_PASSWORD_HASH'] = 'bcrypt'
app.config['SECURITY_PASSWORD_SALT'] = b'$2b$12$wqKlYjmOfXPghx3FuC3Pu.'

# Create database connection object
db = SQLAlchemy(app)

# Define models
roles_users = db.Table('roles_users',
        db.Column('user_id', db.Integer(), db.ForeignKey('user.id')),
        db.Column('role_id', db.Integer(), db.ForeignKey('role.id')))

class Role(db.Model, RoleMixin):
    id = db.Column(db.Integer(), primary_key=True)
    name = db.Column(db.String(80), unique=True)
    description = db.Column(db.String(255))

class User(db.Model, UserMixin):
    id = db.Column(db.Integer, primary_key=True)
    email = db.Column(db.String(255), unique=True)
    password = db.Column(db.String(255))
    active = db.Column(db.Boolean())
    confirmed_at = db.Column(db.DateTime())
    roles = db.relationship('Role', secondary=roles_users,
                            backref=db.backref('users', lazy='dynamic'))

# Setup Flask-Security
user_datastore = SQLAlchemyUserDatastore(db, User, Role)
security = Security(app, user_datastore)

# Create a user to test with
@app.before_first_request
def create_user():
    try:
        db.create_all()
        user_datastore.create_user(email='[email protected]', password='password')
        db.session.commit()
    except:
        db.session.rollback()
        print("User created already...")

# Views
@app.route('/')
@login_required
def home():
    return render_template('index.html')

if __name__ == '__main__':
    app.run()

Answer 1

而不是存储密码，您可以使用python的本机装饰器来存储密码的散列版本，并且出于安全目的使密码不可读，如下所示：

class User(db.Model, UserMixin):
    id = db.Column(db.Integer, primary_key=True)
    email = db.Column(db.String(255), unique=True)
    password_hash = db.Column(db.String(128))

    @property
    def password(self):
        raise AttributeError('password not readable')
    @password.setter
    def password(self, password):
        self.password_hash = bcrypt.hashpw('password', bcrypt.gensalt()))
        # or whatever other hashing function you like.

您应该使用您实施的bcrypt技术内嵌添加验证密码功能：

    def verify_password(self, password)
        return some_check_hash_func(self.password_hash, password)

然后你可以用通常的方式创建一个用户：

User(email='[email protected]', password='abc')

并且您的数据库应填充散列的password_hash而不是password属性。