Here is my code.
#include <bits/stdc++.h>
using namespace std;
class Node {
public:
int data;
Node* next;
};
void printList(Node* n)
{
while (n != NULL) {
cout << n->data << " ";
n = n->next;
}
}
void delete_list(Node *n)
{
Node *tmp = NULL;
tmp = new Node();
while (n != NULL){
tmp=n->next;
delete (Node *)n;
n=tmp;
}
delete (Node *)tmp;
}
int main()
{
Node* head = NULL;
Node* second = NULL;
Node* third = NULL;
head = new Node();
second = new Node();
third = new Node();
head->data = 1;
head->next = second;
second->data = 2;
second->next = third;
third->data = 3;
third->next = NULL;
printList(head);
// Delete the entire list
delete_list(head);
return 0;
}
enter code here
退出时使用:1块中的16个字节堆总使用量:6个分配,5个释放,73,792字节分配1块中的16个字节肯定在1的丢失记录中丢失在0x4C3017F:运算符new(unsigned long)(在/usr/lib/valgrind/vgpreload_memcheck-amd64-linux.so中)通过0x10895E:delete_list(Node *)(demo.cpp:24)通过0x108A87:主(demo.cpp:58)泄漏摘要:绝对丢失:1个块中的16个字节间接丢失:0字节(0块)可能丢失:0字节(0块)仍可访问:0字节(0块)已抑制:0字节,0块有关检测到和抑制的错误的计数,请重新运行:-v错误摘要:来自1个上下文的1个错误(禁止显示:0至0)void delete_list(Node *n)
{
Node *tmp = NULL;
// this is your memory leak:
// you just created a new node ...
tmp = new Node();
while (n != NULL)
{
// ... and very first thing you do is assigning another node to the only
// pointer holding the node created just before
tmp = n->next;
delete (Node *)n;
n = tmp;
}
// apart from cast being obsolete (tmp HAS appropriate type!)
// tmp is already nullptr and you don't delete anything at all
delete (Node *)tmp;
}
此示例很好地说明了为什么最好将变量保持在尽可能局部的位置:
while (n != NULL)
{
Node* tmp = n->next;
delete (Node *)n;
n = tmp;
}
您根本无法在不需要时分配任何东西(甚至创建不相关的对象)或试图删除不再存在的东西...
是的,我做了同样的事情。谢谢你们。
void delete_list(Node *n)
{
Node *tmp = NULL;
// tmp = new Node();
while (n != NULL){
tmp=n->next;
delete (Node *)n;
n=tmp;
}
// delete (Node *)tmp;
}
现在没有内存泄漏。 :)Memcheck,内存错误检测器版权所有(C)2002-2017,以及Julian Seward等人的GNU GPL。使用Valgrind-3.13.0和LibVEX;使用-h重新运行以获取版权信息命令:./ a.out1 2 3文件描述符:3在出口打开。打开文件描述符2:/ dev / pts / 3打开文件描述符1:/ dev / pts / 3打开文件描述符0:/ dev / pts / 3堆摘要:在出口使用:0字节,0块堆总使用量:5个分配,5个释放,73,776字节分配所有堆块都已释放-不可能泄漏有关检测到和抑制的错误的计数,请重新运行:-v错误摘要:0个上下文中的0个错误(禁止显示:0个中的0个)