如何在当前迭代中更新一个矩阵，同时使用cplex opl中的主函数保留先前迭代的值？ 我想更新具有当前迭代值以及主函数中的先前迭代值的矩阵。 请帮助我实现这一目标。我尝试了此代码。 int tslots = 96; ...

Question

I将稍微更改我在

Https：//github.com/alexfleischerparis/howtowithoplchange/blob/master/master/change2darray.mod

解释我将如何使用流量控制main做到这一点的示例。 sub2d.mod

int y[1..2][1..2]=...;

execute
{
writeln("y=",y);
}

dvar float x;

maximize x;
subject to {
  x<=sum(i in 1..2, j  in 1..2) y[i][j];
}

Answer 1

如果你写

range r2=1..2;
int a[r2][r2];

int nbMaxIterations=100;
int storeamongiterations[1..nbMaxIterations][r2][r2];

    main {
      var source = new IloOplModelSource("sub2d.mod");
      var cplex = new IloCplex();
      var def = new IloOplModelDefinition(source);
     
     
     
      for(var k=11;k<=15;k++)
      {
      var opl = new IloOplModel(def,cplex);
     
     
        
      var data2= new IloOplDataElements();
     
      data2.y=thisOplModel.a;
      data2.y[1][1]=k;
      opl.addDataSource(data2);
      
      // Save the values
      for(var i in thisOplModel.r2) for(var j in thisOplModel.r2) 
      thisOplModel.storeamongiterations[k][i][j]=data2.y[i][j];
      
     
      opl.generate();

      if (cplex.solve()) {
         writeln("OBJ = " + cplex.getObjValue());
      } else {
         writeln("No solution");
      }
      data2.end();
     opl.end();
     
     
     
    }  
    
    
    // and now let's display all the values we saved
    
     for(var k=11;k<=15;k++)
     {
       write("for k = ",k," the values in the matrix y are ");
       for(var i in thisOplModel.r2) for(var j in thisOplModel.r2) write(thisOplModel.storeamongiterations[k][i][j]," ");
       writeln();
     }
    }

然后你得到了

y= [[11 0]
         [0 0]]
OBJ = 4
y= [[12 0]
         [0 0]]
OBJ = 3
y= [[13 0]
         [0 0]]
OBJ = 4
y= [[14 0]
         [0 0]]
OBJ = 3
y= [[15 0]
         [0 0]]
OBJ = 4
for k = 11 the values in the matrix y are 11 0 0 0 
for k = 12 the values in the matrix y are 12 0 0 0 
for k = 13 the values in the matrix y are 13 0 0 0 
for k = 14 the values in the matrix y are 14 0 0 0