Snowflake SQL Pivot/基于变量组转置行

Question

这是我的起始数据表的示例

我想将数据翻转为如下所示 - 对于状态 fips、年份和 id 的每个唯一组合，其中有 status1-status？状态值的数量未知，并且可能根据数据而变化。

我一直在研究pivot，但似乎无法获得正确的语法。该文档使用聚合，但我只需要转置信息。

这是一些代码和我的一些尝试。

create or replace temporary table try1
(fips integer, yr integer, id varchar(5), status varchar(10));

insert into try1
values
(20,2022,47250,'03 ACTIVE'),
(20,2022,47250,'79 TERM'),
(20,2023,47250,'79 TERM'),
(20,2022,56957,'83 TERM'),
(20,2023,56957,'03 ACTIVE'),
(20,2023,56957,'83 TERM'),
(20,2022,57645,'79 TERM'),
(20,2023,57645,'03 ACTIVE'),
(20,2023,57645,'79 TERM'),
(20,2023,57645,'83 TERM');

select *, 1 as flag from try1
pivot(sum(flag)) for status in (any order status)
order by id;

select *, 1 as flag from try1
pivot(flag) for status in (any order status)
order by id;

select * from try1
pivot(for status in (any order status))
order by id;

Answer 1

正如其他人建议稍后解析它，您可以使用array_unique_agg

with try1(fips, yr, id, status ) as (
    select * from values
    (20,2022,47250,'03 ACTIVE'),
    (20,2022,47250,'79 TERM'),
    (20,2023,47250,'79 TERM'),
    (20,2022,56957,'83 TERM'),
    (20,2023,56957,'03 ACTIVE'),
    (20,2023,56957,'83 TERM'),
    (20,2022,57645,'79 TERM'),
    (20,2023,57645,'03 ACTIVE'),
    (20,2023,57645,'79 TERM'),
    (20,2023,57645,'83 TERM')
)
select 
    fips,
    yr,
    id,
    array_unique_agg(status) as status_array
from try1
group by 1,2,3
order by 1,3,2;