将一个具有不同列值的重复唯一id的表转换为单行。

Question

我正试图转换我的数据的当前格式 1 转换成图像格式 2. 正如你所看到的数据目前被分割成两行，每一个cust_id都有一个代码，但我希望它在一行。一个给定的代码的open和response是相互排斥的1，即代码A的custx没有匹配的分配值1 & 1的open和response，但可以有0 & 0，1 & 0或0 & 1.我使用的是Oracle SQL Developer 19.2.1。先谢谢你

当前SQL数据格式

希望的SQL数据格式

Answer 1

尝试以下，这里是 演示.

select
    cust_key,
    min(case when code = 'A' then open end) as A_open,
    min(case when code = 'B' then open end) as B_open,
    min(case when code = 'A' then replied end) as A_replied,
    min(case when code = 'B' then replied end) as B_replied
from yourTable
group by
    cust_key

输出。

|cust_key    A_open  B_open  A_replied  B_replied |
---------------------------------------------------
| cust1          0       0          1         0   |
| cust2          0       0          1         1   |
---------------------------------------------------

Answer 2

你可以使用 "PIVOT"，如下所示。

with xxx as (
select 'cust1' custkey,'A' code, 0 opened,1 replied from dual
union all
select 'cust1' custkey,'B' code, 0 opened,0 replied from dual
union all
select 'cust2' custkey,'A' code, 0 opened,1 replied from dual
union all
select 'cust2' custkey,'B' code, 0 opened,1 replied from dual
)
    SELECT  *  FROM 
(
    select xxx.* from XXX
)
PIVOT
(
    sum(opened) as OPENED,sum(replied) REPLIED  FOR (CODE) IN ('A' AS A,'B' AS B) 
)
    group by custkey,a_opened,a_REPLIED,b_opened,b_REPLIED