使用Pythonconfigparser

Question

config.ini
[settings]
videofile = video.avi
codesplit = -vn
outputfile = audio.mp3

输出

['ffmpeg.exe', '-i', 'video.avi', '-vn', 'audio3.mp3']

如果您将值“代码”为空，则代码将不起作用。 示例：将视频AVI文件转换为视频MP4

[settings]
videofile = video.avi
codesplit = 
outputfile = videoaudio.mp4

输出

['ffmpeg.exe', '-i', 'video.avi', '', 'videoaudio.mp4']

我想删除此报价，以便代码可行

 '',

Full代码

import subprocess
import configparser


config = configparser.ConfigParser(allow_no_value=True)
config.read(r'config.ini')
videofile = config.get('settings', 'videofile')
outputfile = config.get('settings', 'outputfile')
codesplit = config.get('settings', 'codesplit', fallback=None)



ffmpeg_path = r"ffmpeg.exe"


command = [
    f"{ffmpeg_path}",
    "-i", (videofile),
    (codesplit),
    (outputfile),]

process = subprocess.Popen(
    command,
    stdout=subprocess.PIPE,
    stderr=subprocess.PIPE,
    text=True,
    bufsize=1,
    universal_newlines=True)
process.communicate()

print(command)

您可以尝试使用IF-ELSE语句检查是否有从配置文件传递的

codesplit

Answer 1

import subprocess
import configparser


config = configparser.ConfigParser(allow_no_value=True)
config.read(r"config.ini")
videofile = config.get("settings", "videofile")
outputfile = config.get("settings", "outputfile")
codesplit = config.get("settings", "codesplit", fallback=None)


ffmpeg_path = r"ffmpeg.exe"

if codesplit:
    command = [
        f"{ffmpeg_path}",
        "-i",
        (videofile),
        (codesplit),
        (outputfile),
    ]
else:
    command = [
        f"{ffmpeg_path}",
        "-i",
        (videofile),
        (outputfile),
    ]

process = subprocess.Popen(
    command,
    stdout=subprocess.PIPE,
    stderr=subprocess.PIPE,
    text=True,
    bufsize=1,
    universal_newlines=True,
)
process.communicate()

print(command)

该代码检查是否在配置中是否存在。如果是这样，它将其添加到

codesplit

列表中。如果没有，则不会。

输出看起来像

command

没有空字符串的地方。