列名与使用SELECT变量作为INSERT值的表不匹配

问题描述 投票:0回答:1

我创建了一个存储过程,必要时将INSERT / UPDATE。我正在使用此方法来评估是否必须插入:

INSERT INTO X
SELECT @A, @B, @C -- Exactly as the table, all nullables
WHERE NOT EXISTS (SELECT * from ... WHERE condition)

但我收到了

消息213,级别16,状态1,过程ArtigoEAN_Remover,行48 [批处理开始行7]列名称或提供的值的数量与表定义不匹配。

这是我的完整代码(我用信号表示第48行):

@ArtigoID AS varchar(14),
@TipoArtigo AS varchar(3),
@CodBarras AS varchar(24)

AS
BEGIN
-- SET NOCOUNT ON added to prevent extra result sets from interfering with SELECT statements.
SET NOCOUNT ON;

    IF (@ArtigoID IS NOT NULL AND @TipoArtigo IS NULL) OR (@ArtigoID IS NULL AND @TipoArtigo IS NOT NULL)
    BEGIN
        PRINT 'Tem que escolher ArtigoID & TipoArtigo para remover código EAN da referência.'
        RETURN
    END
    --
    IF (@CodBarras IS NOT NULL) AND (@ArtigoID IS NOT NULL OR @TipoArtigo IS NOT NULL)
    BEGIN
        PRINT 'Escolher Código EAN apenas (Para remover esse código de barras de todas as referências) OU ArtigoID + TipoArtigo (remover todos os códigos EAN associados a essa referência)'
        RETURN
    END
    --
    IF @ArtigoID IS NOT NULL AND @TipoArtigo IS NOT NULL 
    BEGIN 

    UPDATE [s].[dbo].[FArtigo]
    SET CodBarras = ''
    WHERE ArtigoID = @ArtigoID AND TipoArtigo = @TipoArtigo AND CodBarras = @CodBarras
    -- LINE 48
    INSERT INTO [s].[dbo].[Infolog_ArtigoEAN] 
    SELECT @ArtigoID,@TipoArtigo,@CodBarras
    WHERE NOT EXISTS (SELECT * FROM [s].[dbo].[Infolog_ArtigoEAN] WHERE ArtigoID = @ArtigoID AND TipoArtigo = @TipoArtigo AND CodBarras = @CodBarras)
    -- Inserts above if nox exist, update below in any case.
    UPDATE [s].[dbo].[Infolog_ArtigoEAN] SET CodBarras = '' WHERE ArtigoID = @ArtigoID AND TipoArtigo = @TipoArtigo AND CodBarras = @CodBarras

    INSERT INTO [s].[dbo].[ArtigoEAN]
    SELECT @ArtigoID,@TipoArtigo,@CodBarras
    WHERE NOT EXISTS (SELECT * FROM [s].[dbo].[Infolog_ArtigoEAN] WHERE ArtigoID = @ArtigoID AND TipoArtigo = @TipoArtigo AND CodBarras = @CodBarras)
    UPDATE [s].[dbo].[ArtigoEAN] SET CodBarras = '' WHERE ArtigoID = @ArtigoID AND TipoArtigo = @TipoArtigo AND CodBarras = @CodBarras

    END
    --
    IF @CodBarras IS NOT NULL AND (@ArtigoID IS NULL AND @TipoArtigo IS NULL) 
    BEGIN

    UPDATE [s].[dbo].[FArtigo] SET CodBarras = '' WHERE CodBarras = @CodBarras
    UPDATE [s].[dbo].[Infolog_ArtigoEAN] SET CodBarras = '' WHERE CodBarras = @CodBarras
    UPDATE [s].[dbo].[ArtigoEAN] SET CodBarras = '' WHERE CodBarras = @CodBarras

    END
END

所以我的问题是,为什么它在第48行之后尝试执行INSERT,当我只是改变(保存)过程时,我甚至没有使用参数运行它。

请记住,我想使用SELECT作为条件INSERT(INSERT INTO dbo.Example SELECT(to,insert,if,true)WHERE NOT EXISTS(SELECT * FROM dbo.Example WHERE myCondition = notExist)

sql-server tsql if-statement select where-clause
1个回答
0
投票

您收到此错误,因为表中的列数和您在insert语句中指定的值的数量不匹配。

在您的查询中,您提供了3个值,因此您的表中可能有超过3列或少于3列。

为了避免将来出现这种错误,而不是指定

INSERT INTO TableName
VALUES(1,2,3)

指定y要插入值的列名称。像这样

INSERT INTO TableName(Col1,Col2,Col3)
VALUES(1,2,3)

要么

INSERT INTO X(Col1,Col2,Col3)
SELECT @A, @B, @C

您不需要运行脚本/过程来获取错误,SQL Server将在编译时返回错误,即;当您尝试创建或更改过程时

© www.soinside.com 2019 - 2024. All rights reserved.