如何在for循环中用空格分隔值

Question

因此，我有这个程序，可以给出ascii值的二进制值加上用户输入字符串的1。

text = input()
bitString = ''
for ch in text:
    new = ord(ch) + 1

    decimal = new
    while decimal > 0:
        remainder = decimal % 2
        decimal = decimal // 2
        bitString = str(remainder) + bitString

print(bitString)

如果用户输入“ abcde”，则输出为

11001101100101110010011000111100010

如何获得二进制值，用空格分隔，输出将在哪里

1100010 1100011 1100100 1100101 1100110

？

Answer 1

尝试像这样最后使用空格

    remainder = decimal % 2
    decimal = decimal // 2
    bitString = str(remainder) + bitString + " "

这应该解决

Answer 2

在您的代码中稍作更改以增加空间：

text = input()
bitString = ''
for ch in text:
    new = ord(ch) + 1

    decimal = new
    while decimal > 0:
        remainder = decimal % 2
        decimal = decimal // 2
        bitString = str(remainder) + bitString

    bitString = " " + bitString

print(bitString)

输出：

1100010 1100011 1100100 1100101 1100110

Answer 3

尝试一下：

revBitString = bitString[::-1]
print(' '.join([revBitString[i:i+7][::-1] for i in range(0,len(revBitString),7)]))

Answer 4

这里是解决方法：

text = input()
bitString = ''
for ch in text:
    new = ord(ch) + 1

    decimal = new
    while decimal > 0:
        remainder = decimal % 2
        decimal = decimal // 2
        bitString = str(remainder) + bitString
splitStr = [bitString[i:i+7] for i in range(0, len(bitString), 7)]
print(" ".join(splitStr[::-1]))

结果：

1100010 1100011 1100100 1100101 1100110

OR

text = input()
bitString = ''
for ch in text:
    new = ord(ch) + 1
    decimal = new
    while decimal > 0:
        remainder = decimal % 2
        decimal = decimal // 2
        bitString = str(remainder) + bitString
    bitString = " " + bitString

print(" ".join(bitString.split()[::-1]))

结果：

1100010 1100011 1100100 1100101 1100110

Answer 5

input = 'abcde'
bitString = ''
for i in list(input):
    bitString =  bitString + bin(ord(i)+1)[2:] + ' '
print(bitString)

我希望你想这样。