你能帮我在 Collimator 中实现这个欧拉函数吗?
function [t,y] = MyEuler(f,tinterval,y0,n)
y = zeros(n+1,1) // y vector of zeroes
y(1) = y0 //y0 is the first element of the y vector
dt = (tinterval(2)-tinterval(1))/n //step size
//disp('dt')
t = tinterval(1):dt:tinterval(2)
for i = 1:n
y(i+1) = y(i)+f(t(i),y(i))*dt
end
t = t'
endfunction ```
您的编写几乎正确,几乎没有语法错误,因此这是一个没有任何错误的重新访问版本。
function [t, y] = MyEuler(f, tinterval, y0, n)
% Initialize the vector of zeros for y
y = zeros(n+1, 1); % y vector of zeroes
y(1) = y0; % y0 is the first element of the y vector
% Calculate the step size
dt = (tinterval(2) - tinterval(1)) / n;
% Create the time vector t
t = linspace(tinterval(1), tinterval(2), n+1);
% Euler's method loop
for i = 1:n
y(i+1) = y(i) + f(t(i), y(i)) * dt;
end
% Transpose t to ensure it matches the output format
t = t';
end
这是运行上述函数的测试代码
% Define the differential equation dy/dt = y - t^2 + 1
f = @(t, y) y - t^2 + 1;
% Set the time interval [t0, tf], initial condition y0, and number of steps n
tinterval = [0, 2];
y0 = 0.5;
n = 10;
% Call the MyEuler function
[t, y] = MyEuler(f, tinterval, y0, n);