批处理文件错误句柄

Question

我有批处理文件，执行我的PHP脚本，但我不知道如何处理空的参数，你能帮帮我吗？

这是我的批处理脚本

echo off
set phppath=%1
set resultfolder=%2
set jsonfile=%3
shift
shift
shift

set PHP_HOME=%phppath%
set PATH=%PATH%;%PHP_HOME%
echo Set PHP_HOME in "%phppath%"
echo Locate result in folder "%resultfolder%"
echo JSON file is "%jsonfile%"


pause;
php -f cxense_json_to_xml.php %resultfolder% %jsonfile%

Answer 1

@echo off
set phppath=%1
set resultfolder=%2
set jsonfile=%3
set PHP_HOME=%phppath%
set PATH=%PATH%;%PHP_HOME%
echo Set PHP_HOME in "%phppath%"
echo Locate result in folder "%resultfolder%"
echo JSON file is "%jsonfile%"
php -f cxense_json_to_xml.php %resultfolder% %jsonfile%
Pause

批处理必须像这样开始：

Batch.bat "path to PHP" "path to result folder" "name of jsonfile"

暂停后没有分号。