春季启动com.fasterxml.jackson.core.JsonParseException:无法识别的记号

问题描述 投票:1回答:1

我与春天启动的项目工作,我想在程序启动后,而不是事后手动使用curl执行多个POST请求。其目的将是存储在存储一些数据,使平台准备好进一步的操作。原来cURL命令我使用(这工作得很好),

$ curl -i -X POST -H "Content-Type:application/json" -d "{\"name_of_doctor\" : \"Monika2\", \"price\": \"12.5\"}" http://localhost:8080/api/v1/appointments/createAppointment 

这需要它的API,

@PostMapping(value = "/createAppointment", consumes = "application/json;charset=UTF-8", produces = "application/json;charset=UTF-8")
    public ResponseEntity<Appointment> create(@RequestBody Appointment appointment) {

        java.sql.Date date = new java.sql.Date(Calendar.getInstance().getTime().getTime());
        java.sql.Time time = new java.sql.Time(Calendar.getInstance().getTime().getTime());

        appointment.setAppointment_date(date);
        appointment.setCraeted_at(time);

        // we create the appointment, because, the doctor is available
        appointment.setStatus(new Status(true));
//        appointment.setStatus(true);

        service.save(appointment);
        return ResponseEntity.status(HttpStatus.CREATED).body(appointment);
    }

现在我把Spring启动加载它之后,

@SpringBootApplication
@EnableTransactionManagement
public class AppointmentApplication {

    public static void main(String[] args) {



        System.out.println("\n\nAppointment Manager\n\n");
        SpringApplication.run(AppointmentApplication.class, args);



        HttpClient client = HttpClientBuilder.create().build();
        HttpPost post = new HttpPost("http://localhost:8080/api/v1/appointments/createAppointment");


        List<NameValuePair> arguments = new ArrayList<>(2);

        arguments.add(new BasicNameValuePair("name_of_doctor", "Monika"));
        arguments.add(new BasicNameValuePair("price", "12.5"));

        try {
            post.setEntity(new UrlEncodedFormEntity(arguments));
//post.addHeader("content-type", "application/x-www-form-urlencoded");
        post.setHeader("Accept", "application/json");
        post.setHeader("Content-type", "application/json");

            HttpResponse response = client.execute(post);

            System.out.println(EntityUtils.toString(response.getEntity()));
        } catch (IOException e) {
            e.printStackTrace();
        }
    }
}

我得到提供了以下错误,

{"timestamp":"2019-02-09T06:45:36.393+0000","status":400,"error":"Bad Request","message":"JSON parse error: Unrecognized token 'name_of_doctor': was expecting 'null', 'true', 'false' or NaN; nested exception is com.fasterxml.jackson.core.JsonParseException: Unrecognized token 'name_of_doctor': was expecting 'null', 'true', 'false' or NaN\n at [Source: (PushbackInputStream); line: 1, column: 16]","path":"/api/v1/appointments/createAppointment"}

如何在这种情况下为POST调用正确设置媒体数据?

java spring-boot http curl http-post
1个回答
2
投票

下面的代码将值作为请求参数。

    post.setEntity(new UrlEncodedFormEntity(arguments));

考虑到你的API预计请求主体JSON内容,则需要改用StringEntityUrlEncodedFormEntity

    post.setEntity(new StringEntity("{ \"name_of_doctor\": \"\", \"price\": \"12.5\" }", Charset.forName("UTF-8")));
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