如何获取数组差异

Question

我有 2 个多维数组。

Array1 包含一些可用名称：

Array1
(
[0] => Array
     (
         [quantity] => 13
         [idname] => 3
         [x_name] => Name-3
     )

[1] => Array
    (
        [quantity] => 5
        [idname] => 4
        [x_name] => Name-4
    )

)

和 Array2 包含所有可用名称：

Array2
(
    [0] => Array
        (
            [id_x] => 3
            [x_name] => Name-3
            [id_l] => 4
        )

    [1] => Array
        (
            [id_x] => 4
            [x_name] => Name-4
            [id_l] => 8
        )

    [2] => Array
        (
            [id_x] => 5
            [x_name] => Name-5
            [id_l] => 7
        )

    [3] => Array
        (
            [id_x] => 6
            [x_name] => Name-6
            [id_l] => 5
        )

)

数组1[][idname] = 数组2[][id_x] 和 Array1[][x_name] = Array2[][x_name] (ofc...)

我想要的输出是 Array2 中 Array1 不包含的每个元素......所以：

Arraydesire
(

    [0] => Array
        (
            [id_x] => 5
            [x_name] => Name-5
            [id_l] => 7
        )

    [1] => Array
        (
            [id_x] => 6
            [x_name] => Name-6
            [id_l] => 5
        )

)

我尝试使用 array_intersect 但没有成功。 感谢您的帮助。

Answer 1

您可以使用嵌套的 foreach 循环。如果在 array1 中找到 array2 当前元素的值，则删除该元素：

foreach($array2 as $key => $value){
    foreach($array1 as $val){
        if($value['x_name']==$val['x_name']){
            unset($array2[$key]);
            $break;
        }
    }
}
var_dump($array2);

实例：http://codepad.viper-7.com/eOOUi6

Answer 2

<?php
$arr1 = Array();
$arr1[] = Array('quantity' => 13, 'idname' => 3, 'x_name' => 'Name-3');
$arr1[] = Array('quantity' => 5, 'idname' => 4, 'x_name' => 'Name-4');


$arr2 = Array();
$newTemp = Array();
$arr2[] = Array('id_x' => 3, 'x_name' => 'Name-3', 'id_l' => 4);
$arr2[] = Array('id_x' => 4, 'x_name' => 'Name-4', 'id_l' => 8);
$arr2[] = Array('id_x' => 5, 'x_name' => 'Name-5', 'id_l' => 7);
$arr2[] = Array('id_x' => 6, 'x_name' => 'Name-6', 'id_l' => 5);

$newTemp = $arr2;
foreach ($arr1 as $subArray1) {
    foreach ($arr2 as $key => $subArray2) {
        if ($subArray1['x_name']==$subArray2['x_name']) {
            unset($newTemp[$key]);
            break;
        }
    }
}
print_r($arr1);
print_r($arr2);
print_r($newTemp);
?>

Answer 3

由于

array_u*()

函数的回调不知道要比较的两个变量的源数组，因此比较脚本必须尝试像访问一个数组一样访问数据，然后在需要时回退到另一个数组。

使用 spaceship 运算符对由指定数据点组成的两个临时数组进行三向比较。 演示

var_export(
    array_udiff(
        $array2,
        $array1,
        fn($a, $b) => [$a['idname'] ?? $a['id_x'], $a['x_name']]
                      <=>
                      [$b['idname'] ?? $b['id_x'], $b['x_name']]
    )
);

输出：

array (
  2 => 
  array (
    'id_x' => 5,
    'x_name' => 'Name-5',
    'id_l' => 7,
  ),
  3 => 
  array (
    'id_x' => 6,
    'x_name' => 'Name-6',
    'id_l' => 5,
  ),
)