如何替换一个字符并在其下一行的前面添加另一个字符？

Question

我的目标是在特定行的末尾用

/

覆盖

-

字符，然后在该行的前面以及该行下一行的前面插入一个

-

。我所做的测试是使用 sed 如下：

$ cat input | sed -E 'N;s/^(- )?(.*\n)\//- \2-/;P;D'
$ cat input | sed 'N; \#\n/# { s//\n-/; s/^/- / }; P;D'
$ cat input | sed -E 'N;s|([^\n]*\n)/|- \1-|;P;D'
$ cat input | sed -Ez 's|([^\n]*\n)/|- \1-|g'

我的输入：

1
00:00:00,000 --> 00:00:00,000
<b><font color="#ffffff">Lorem Ipsum</font></b>

2
00:00:00,000 --> 00:00:00,000
Lorem ipsum dolor sit/
amet, consectetur adipiscing elit.

3
00:00:00,000 --> 00:00:00,000
Ut sed gravida nisi.

4
00:00:00,000 --> 00:00:00,000
Nunc sit amet ultrices urna,/
non efficitur neque. 

5
00:00:00,000 --> 00:00:00,000
<b><font color="#ffffff">Cras aliquam tristique dui, viverra laoreet diam hendrerit ac.</font></b>

我的期望：

00:00:00,000 --> 00:00:00,000
<b><font color="#ffffff">Lorem Ipsum</font></b>

2
00:00:00,000 --> 00:00:00,000
- Lorem ipsum dolor sit
- amet, consectetur adipiscing elit.

3
00:00:00,000 --> 00:00:00,000
Ut sed gravida nisi.

4
00:00:00,000 --> 00:00:00,000
- Nunc sit amet ultrices urna,
- non efficitur neque. 

5
00:00:00,000 --> 00:00:00,000
<b><font color="#ffffff">Cras aliquam tristique dui, viverra laoreet diam hendrerit ac.</font></b>

Answer 1

与

awk

：

awk 'flag  {flag = 0; print "- " $0}
     /\/$/ {flag = 1; print "- " substr($0, 1, length($0) - 1)} input