成功后重定向URL

Question

import re
DEFAULT_SUCCESS_URL = re.compile(r'^(?P<clientcode>[0-9]{9})/dashboard/')
url(r'^(?P<clientcode>[0-9]{9})/order/$',
    OrderFormView.as_view(success_url=settings.DEFAULT_SUCCESS_URL),
    name='zoneclient-order'),

到目前为止，由于以下错误，该技术无效：

TypeError: unsupported operand type(s) for %: '_sre.SRE_Pattern' and 'dict'

事实上，我希望success_url成为

  # Dashboard
  url(r'^(?P<clientcode>[0-9]{9})/dashboard/', login_required(
      DashboardView.as_view()), name='zoneclient-dashboard'),

如何修改顶部代码才能与r'^(?P<clientcode>[0-9]{9})/dashboard/'一起使用？

附：请注意，我正在使用Django 1.7和DEFAULT_SUCCESS_URL多次使用。

UPDATE

class OrderFormView(CustomerViewMixin, CreateView, SendTextEmailMixin):
    template_name = 'zoneclient/order-form.html'
    form_class = OrderForm

    email_subject_template = 'zoneclient/emails/order_form_subject.txt'
    email_body_template = 'zoneclient/emails/order_form_body.txt'
    email_recipients = settings.EMAIL_NOTIFY_ORDERS

    def get_form(self, form_class):
        kwargs = self.get_form_kwargs()
        kwargs['user'] = self.get_customer()
        return form_class(**kwargs)

    def form_valid(self, form):
        self.object = form.save()
        self.send_email()
        log.info('%s\' order #%d was successufully processed.' % (\
            usr(self.request), self.object.id))
        messages.success(
            self.request,
            _('Your order has been placed, thank you!'),
            fail_silently=True)
        return HttpResponseRedirect(self.get_success_url())

    def get_email_context(self):
        context = super(OrderFormView, self).get_email_context()
        context['user'] = self.get_customer()
        context['object'] = self.object
        return context

Answer 1

这是一个显示如何覆盖get_success_url()的示例。你没有提供视图类的实现，所以我认为它是一个标准的qazxsw poi。

FormView

您可以参考Django文档了解详细信息。