如何用另一个数组替换多维数组中的某些值

Question

我尝试用具有相同键的另一个数组替换多维数组中的某些值 但结果却替换了所有值

这是我的示例数组

[
    {
        "book_id": 45,
        "language_code": "RUWT-EN",
        "book_name": Study,
        "country": "Singapore",
        "created_by": 12,
        "created_date": "2019-04-09 09:19:24",
        "update_by": 12,
        "update_date": "2019-06-25 03:57:52",
        "status": "1",
    },
    {
        "book_id": 46,
        "language_code": "RUWT-EN",
        "book_name": Sleep,
        "country": "Indonesia",
        "created_by": 12,
        "created_date": "2019-04-09 09:19:24",
        "update_by": 12,
        "update_date": "2019-06-25 03:57:52",
        "status": "1",
    },
    {
        "book_id": 47,
        "language_code": "RUWT-EN",
        "book_name": Teaching,
        "country": "China",
        "created_by": 12,
        "created_date": "2019-04-09 09:19:24",
        "update_by": 12,
        "update_date": "2019-06-25 03:57:52",
        "status": "1",
    },
]

这是我的第二个数组

[
    {
        "book_id": 45,
        "language_code": "RUWT-CH",
        "book_name": Study in CH,
        "country": "Korea",
        "status": "2",
    },
    {
        "book_id": 46,
        "language_code": "RUWT-CH",
        "book_name": Sleep in CH,
        "country": "US",
        "status": "2",
    },
    {
        "book_id": 47,
        "language_code": "RUWT-CH",
        "book_name": Teaching in CH,
        "country": "England",
        "status": "2",
    },
]

我尝试过使用 laravel 地图集合并 foreach 一个一个的值，然后替换具有相同键的值，但它太长了。我想 最简单的方法

$result = $collect_real->map(function($item) use($lang){
              return $item['book_name'] = $lang->where('book_id', $item['book_id'])->values();
            });

我想要这样的结果

[
    {
        "book_id": 45,
        "language_code": "RUWT-CH",
        "book_name": Study in CH,
        "country": "Korea",
        "created_by": 12,
        "created_date": "2019-04-09 09:19:24",
        "update_by": 12,
        "update_date": "2019-06-25 03:57:52",
        "status": "2",
    },
    {
        "book_id": 46,
        "language_code": "RUWT-CH",
        "book_name": Sleep in CH,
        "country": "US",
        "created_by": 12,
        "created_date": "2019-04-09 09:19:24",
        "update_by": 12,
        "update_date": "2019-06-25 03:57:52",
        "status": "2",
    },
    {
        "book_id": 47,
        "language_code": "RUWT-CH",
        "book_name": Teaching in CH,
        "country": "England",
        "created_by": 12,
        "created_date": "2019-04-09 09:19:24",
        "update_by": 12,
        "update_date": "2019-06-25 03:57:52",
        "status": "2",
    },
]

Answer 1

函数array_replace_recursive用一行代码解决了您的问题：

来自文档：

array_replace_recursive() 将 array1 的值替换为以下所有数组中的相同值。如果第一个数组中的键存在于第二个数组中，则其值将被第二个数组中的值替换。如果该键存在于第二个数组中，而不是第一个数组中，则它将在第一个数组中创建。如果某个键仅存在于第一个数组中，则它将保持原样。如果传递多个数组进行替换，它们将按顺序处理，后面的数组会覆盖前面的值。

array_replace_recursive() 是递归的：它将递归到数组并对内部值应用相同的过程。

示例：

$updatedBooks = array_replace_recursive($wrongBooksArray, $correctBooksArray);