我创建了一个远程方法来对我的数据库进行多次查询,我想在那里找到最多可以同时创建12个用户模型。在loopback explorer中,我传递了这个数组,["player0", "player1", "player2"]
到我的函数,我知道这些函数已经在我的数据库中了。但是,我遇到的问题是我返回状态200和一个空值数组。如果我传递不在DB中的名称,则返回每个名称的对象,其中包含所有默认值。所以我的问题是我的代码的查找部分出了什么问题?
我已经尝试将where子句添加到我的findOrCreate,它仍然返回一个null数组。
更新:这是整个方法
function getPlayerStats(names) {
console.log('names: ', names);
return new Promise((resolve, reject) => {
const { Player } = app.models;
const playerData = names.map(name => {
console.log('single name: ', name);
const defaultSkill = 1500;
return Player.findOrCreate(
{ where: { name: name } },
{
name: name,
careerSkill: defaultSkill,
careerHighestSkill: defaultSkill,
careerWins: 0,
careerLosses: 0,
careerPercent: 0,
careerBestLeader: 'none',
careerAllLeader: ['none'],
highestCareerSkill: defaultSkill,
careerSeasonWins: 0,
careerSeasonLosses: 0,
careerSeasonPercent: 0
}
);
});
Promise.all(playerData)
.then(results => resolve(results))
.catch(err => reject(new Error('could not return results')));
});
}
module.exports = { getPlayerStats };```
我认为你应该在return
Player.findOrCreate({name: name},
正确版本的过滤器之前添加Player.findOrCreate({ where: { name: name } },...
。此外,你可以省略回调(err) => {
,因为你有catch
块
整个功能可能看起来像:player.js
Player.getPlayerStats = function (names, cb) {
const playerPromises = names.map(name => {
const defaultSkill = 1500;
return Player.findOrCreate({ where: { name: name } }, {
"name": name,
"careerSkill": defaultSkill,
"careerHighestSkill": defaultSkill,
"careerWins": 0,
"careerLosses": 0,
"careerPercent": 0,
"careerBestLeader": "none",
"careerAllLeader": ["none"],
"highestCareerSkill": defaultSkill,
"careerSeasonWins": 0,
"careerSeasonLosses": 0,
"careerSeasonPercent": 0
})
})
Promise.all(playerPromises)
.then(players => cb(null, players))
.catch(err => cb(new Error('could not return results'), null))
}