使用对话框单击单击时在Flutter中编辑Listview项目

问题描述 投票:0回答:1

我是新手,但我要在“编辑”按钮上单击“编辑项目”。在“编辑”上,当用户输入文本时,单击“打开带有文本字段的编辑对话框”,我尝试用特定的项目文本替换它,但是我找不到任何解决方案,请帮帮我。在这里,我附上了布局的屏幕截图,还发布了一些代码。

enter image description here

main.dart

import 'package:flutter/foundation.dart';
import 'package:flutter/material.dart';

void main() {
  runApp(MyApp(
    items: List<String>.generate(100, (i) => "List item $i"),
  ));
}

Future<String> _asyncInputDialog(BuildContext context) async {
  String sampleText = '';
  return showDialog<String>(
    context: context,
    barrierDismissible:
    false, // dialog is dismissible with a tap on the barrier
    builder: (BuildContext context) {
      return AlertDialog(
        title: Text('Enter Text'),
        content: new Row(
          children: <Widget>[
            new Expanded(
                child: new TextField(
                  autofocus: true,
                  decoration: new InputDecoration(
                      labelText: 'Text Here', hintText: 'eg. ABCD'),
                  onChanged: (value) {
                    sampleText = value;
                  },
                ))
          ],
        ),
        actions: <Widget>[
          FlatButton(
            child: Text('Ok'),
            onPressed: () {
              Navigator.of(context).pop(sampleText);
            },
          ),
        ],
      );
    },
  );
}

class MyApp extends StatefulWidget {
  final List<String> items;

  MyApp({Key key, @required this.items}) : super(key: key);

  @override
  _MyAppState createState() => _MyAppState();
}

class _MyAppState extends State<MyApp> {
  @override
  Widget build(BuildContext context) {
    final title = 'Long List';

    return MaterialApp(
      title: title,
      home: Scaffold(
        appBar: AppBar(
          title: Text(title),
        ),
        body: ListView.builder(
          itemCount: widget.items.length,
          itemBuilder: (context, index) {
            return ListTile(
              title: Text('${widget.items[index]}'),
              trailing: RaisedButton(
                child: Text('Edit'),
                color: Colors.pinkAccent,
                onPressed: () async {
                  final String newText = await _asyncInputDialog(context);
                  setState(() {

                  });
                  Scaffold.of(context).showSnackBar(new SnackBar(content: new Text("$newText"),));
                },
              ),
            );
          },
        ),
      ),
    );
  }
}
listview flutter flutter-layout
1个回答
0
投票

在您的ListTile中将items[index] = newText;放在setState((){});中,所以我看起来像这样。

ListTile(
              title: Text('${items[index]}'),
              trailing: RaisedButton(
                child: Text('Edit'),
                color: Colors.pinkAccent,
                onPressed: () async {
                  final String newText = await _asyncInputDialog(context);
                  setState(() {
                    items[index] = newText;
                  });
                  Scaffold.of(context).showSnackBar(new SnackBar(
                    content: new Text("$newText"),
                  ));
                },
              ),
            );
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