我的代码中有一个使我难以置信的错误
我每次运行输出都会改变{'A':{'C'},'B':{'A'},'F':{'G'},'E':{'B'},'D':{'E'} ,'C':{'F'}}
当它应该是{'D':{'E'},'E':{'B'},'B':{'A'},'A':{'C'},'C':{'F'} ,'F':{'G'}}
不确定这里到底发生了什么,我尝试调试无济于事。有人知道我是否错过了明显明显的东西吗?
from collections import defaultdict
import heapq
def create_spanning_tree(graph, starting_vertex):
mst = defaultdict(set)
visited = set([starting_vertex])
edges = [
(cost, starting_vertex, to)
for to, cost in graph[starting_vertex].items()
]
heapq.heapify(edges)
while edges:
cost, frm, to = heapq.heappop(edges)
if to not in visited:
visited.add(to)
mst[frm].add(to)
for to_next, cost in graph[to].items():
if to_next not in visited:
heapq.heappush(edges, (cost, to, to_next))
return mst
example_graph = {
'A': {'B': 2, 'C': 3},
'B': {'A': 2, 'C': 12, 'D': 10, 'E': 4},
'C': {'A': 3, 'B': 12, 'F': 5},
'D': {'B': 10, 'E': 7},
'E': {'B': 4, 'D': 7, 'F': 16},
'F': {'C': 5, 'E': 16, 'G': 9},
'G': {'F': 9},
}
print(dict(create_spanning_tree(example_graph, 'D')))
{'A': {'C'}, 'B': {'A'}, 'F': {'G'}, 'E': {'B'}, 'D': {'E'}, 'C': {'F'}}
和{'D': {'E'}, 'E': {'B'}, 'B': {'A'}, 'A': {'C'}, 'C': {'F'}, 'F': {'G'}}
相同。
因为它是字典; (键,值)对很重要,它们在答案中都是相同的,而不是它们出现的顺序。