在使用所需的便利init进行解码时，如何解决“调用中的额外参数？” []：<

Question

我对应用程序开发还比较陌生，正在尝试为使用SwiftUI编写的作业管理应用程序增加持久性。我正在“ UserData”类中实现NSCoding，并且能够毫无问题地创建编码函数，但是在设置解码函数后，我在self.init上收到错误消息“调用中的额外参数'assignments'”（ ）行。我的代码到底有什么问题？

class UserData: NSObject, NSCoding, ObservableObject {

    // MARK:- Properties

    @Published var assignments: [Assignment]
    @Published var courses: [Course] = []

    @Published var username: String = ""
    @Published var appState: AppState = AppState(willPresentSplashScreen: false)

...

 // MARK:- NSCoding

    func encode(with coder: NSCoder) {
        coder.encode(assignments, forKey: PropertyKey.assignments)
        coder.encode(courses, forKey: PropertyKey.courses)
        coder.encode(username, forKey: PropertyKey.username)
        coder.encode(appState, forKey: PropertyKey.appState)
    }

    required convenience init?(coder decoder: NSCoder) {

        let assignments = decoder.decodeObject(forKey: PropertyKey.assignments) as? [Assignment]
        let courses = decoder.decodeObject(forKey: PropertyKey.courses) as? [Course]
        let username = decoder.decodeObject(forKey: PropertyKey.username) as? String
        let appState = decoder.decodeObject(forKey: PropertyKey.appState) as? AppState

        self.init(assignments: assignments, courses: courses, username: username, appState: appState)
    }
}

我对应用程序开发还比较陌生，正在尝试为使用SwiftUI编写的作业管理应用程序增加持久性。我在“ UserData”类中实现了NSCoding，并且能够创建...

Answer 1

init(assignments: [Assignment], courses: [Course], username: String, appState: AppState) {
    self.assignments = assignments
    self.courses = courses
    self.username = username
    self.appState = appState
}

这将给您一个错误，因为您有可选参数，并且初始化程序不希望有可选参数，所以您需要解包从init?(coder decoder: NSCoder)传递来的参数。

init?(coder decoder: NSCoder)是失败的初始化程序，因此如果一切都不正确，则可以返回nil：

required convenience init?(coder decoder: NSCoder) {

        guard let assignments = decoder.decodeObject(forKey: PropertyKey.assignments) as? [Assignment],
            let courses = decoder.decodeObject(forKey: PropertyKey.courses) as? [Course],
            let username = decoder.decodeObject(forKey: PropertyKey.username) as? String,
            let appState = decoder.decodeObject(forKey: PropertyKey.appState) as? AppState else {
                return nil
        }

        self.init(assignments: assignments, courses: courses, username: username, appState: appState)
}
我可能会摆脱分配给courses，username和appState的默认值-您不需要它们，因为这些值将来自初始化程序