如何从url字符串中的列表传递值

Question

我有这个Python脚本的问题。我正在尝试从包含主字符串的列表中传递值。我附上了剧本。在这个命令page = requests.get("https://www.google.dz/search?q=lista[url]")我必须在search?q=之后把我正在寻找的东西放在google上。我想搜索多个关键字，所以我列出了一个列表。我不知道如何传递该命令列表中的值...

import requests
import re
from bs4 import BeautifulSoup

lista = []
lista.append("Samsung S9")
lista.append("Samsung S8")
lista.append("Samsung Note 9")

list_scrape = []

for url in lista:
    page = requests.get("https://www.google.dz/search?q=lista[url]")
    soup = BeautifulSoup(page.content)
    links = soup.findAll("a")
    for link in  soup.find_all("a",href=re.compile("(?<=/url\?q=) 
    (htt.*://.*)")):
        list_scrape.append(re.split(":(?=http)",link["href"].replace("/url?q=","")))

print(list_scrape)

谢谢！

Answer 1

使用format

for url in lista:
    page = requests.get("https://www.google.dz/search?q={}".format(url))

要么

page = requests.get("https://www.google.dz/search?q=%s" % url)

Answer 2

试试这个..

for url in lista:
    page = requests.get("https://www.google.dz/search?q="+url)

要么

page = requests.get("https://www.google.dz/search?q={}".format(url))