将 ASP.net GridView 页面设置为包含给定行的页面的有效方法是什么？

Question

我有一个带有 ASP.net GridView 的网页（带分页）。 GridView 有超过 10,000 行。 每行都有一个“ID”字段。

这是过于简单化了，但假设我希望用户能够在文本字段中键入任意行 ID，并转到 GridView，页面索引自动设置为包含指定行的页面索引身份证。

我已尝试以下方法，但不起作用：

        DataSet ds = ReportManager.GetDevices(AdHocQuery);
        lblRecordCount.Text = String.Format("{0:#,0}", ds.Tables[0].Rows.Count);
        string sortDirection = AdHocQuery.SortDirection == "Descending" ? " DESC" : " ASC";
        DataView dv = new DataView(ds.Tables[0], string.Empty, AdHocQuery.SortColumnName + " " + sortDirection, DataViewRowState.CurrentRows);
        gvAsset.DataSource = dv;
        gvAsset.DataBind();

        // If there was a device ID passed in the Query String, then change the page to the page that contains the given ID.

        if (!string.IsNullOrEmpty(DeviceId))
        {
            // First, find the row number of the given device Id
            int rowNumber = 0;
            int i;
            for (i = 0; i < dv.Table.Rows.Count; i++)
            {
                DataRow row = dv.Table.Rows[i];
                if (row.Field<Guid>("deviceId").ToString().ToUpper() == DeviceId.ToUpper())
                {
                    rowNumber = i;
                    break;
                }
            }

            // The page index is going to be the row Number divided by the Page size
            // For example, if the page size is 10...
            // row 5 is on page 0,
            // row 15 is on page 1,
            // row 28 is on page 2, and so on
            int pageIndex = rowNumber / gvAsset.PageSize;
            gvAsset.PageIndex = pageIndex;

此代码可以编译，但它始终显示 GridView 的错误页面。

我该如何编码才能显示正确的页面？

Answer 1

我相信您需要调用 DataBind() 才能对 PageIndex 属性进行更改。

Answer 2

绑定网格之前调用

gvAsset.PageIndex = pageIndex

Answer 3

你可以尝试这样的事情。它在我的情况下有效。

//assuming there are SomeIDs from 1 to 100 in the database
//assuming pagesize of gridview is 10

DataTable table = GetSomeDataFunction(); //your data retrieval method

for (int i = 0; i < table.Rows.Count; i++)
{
    if (table.Rows[i].Field<int>("SomeID") == 11) //11 = ID you're looking for
    {
        GridView1.PageIndex = (i / GridView1.PageSize);
        break;
    }
}

GridView1.DataSource = table;
GridView1.DataBind();

Answer 4

我已经找到了我自己问题的答案。 在四处寻找答案后，我发现如果我想枚举代码隐藏中的行列表，我需要调用

DataView.GetEnumerator()

函数。 代码如下：

        DataSet ds = ReportManager.GetDevices(AdHocQuery);
        lblRecordCount.Text = String.Format("{0:#,0}", ds.Tables[0].Rows.Count);
        string sortDirection = AdHocQuery.SortDirection == "Descending" ? " DESC" : " ASC";
        DataView dv = new DataView(ds.Tables[0], string.Empty, AdHocQuery.SortColumnName + " " + sortDirection, DataViewRowState.CurrentRows);
        gvAsset.DataSource = dv;
        gvAsset.DataBind();

        // If there was a device ID passed in the Query String, then change the page to the page that contains the given ID.
        if (!string.IsNullOrEmpty(DeviceId))
        {
            // First, find the row number of the given device Id
            int rowNumber = 0;
            int i = 0;

            System.Collections.IEnumerator iterator = dv.GetEnumerator();
            while (iterator.MoveNext())
            {
                DataRowView drv = (DataRowView)iterator.Current;
                DataRow row = drv.Row;
                if (row.Field<Guid>("deviceid").ToString().ToUpper() == DeviceId.ToUpper())
                {
                    rowNumber = i;
                    break;
                }
                i++;
            }                

            // The page index is going to be the row Number divided by the Page size
            // For example, if the page size is 10...
            // row 5 is on page 0,
            // row 15 is on page 1,
            // row 28 is on page 2, and so on
            int pageIndex = rowNumber / gvAsset.PageSize;
            gvAsset.PageIndex = pageIndex;
        }