实数的步骤文件方法

Question

功能：添加小数特征

Scenario: Add two positive decimal numbers
Given I am on the demo page
When I add the numbers 2.25 and 3.25
Then the result is 5.5

我认为when方法应该是这样的

 @When("^I add the numbers (-?\\d+\\.?\\d*) and (-?\\d+\\.?\\d*)$")
public void i_add_the_numbers_and(double x, double y) throws Throwable {
   demoPage.addNumbers(x, y);
}

@Then("^the result is (-?\\d+\\.?\\d*)$")
public void the_result_is(double sum) throws Throwable {
    assertEquals(demoPage.getCalculatorResults(), sum);
}
}

问题是正则表达式的数字与实数不匹配。例如-1.2或5.4或-23.234

如何匹配所有正负实数？

Answer 1

谢谢InvalidData

以下作品

/**
 * @param x
 * @param y
 * @throws Throwable
 */
@When("^I add the numbers (-?\\d+\\.?\\d*) and (-?\\d+\\.?\\d*)$")
public void i_add_the_numbers_and(float x, float y) throws Throwable {
  demoPage.addNumbers(x, y);
}

 /**
 * @param sum
 * @throws Throwable
 */
@Then("^the result is (-?\\d+\\.?\\d*)$")
public void the_result_is(float sum) throws Throwable {
    assertEquals(demoPage.getCalculatorResults(), sum);
}

那么为什么使用float或BigDecimal导致该方法工作？我的理解是double是float的较长版本。所以，如果浮动工作，为什么不会加倍