我有一个CSV文件,其结构如下:
"SA1";"21020180123155514000000000000000002"
"SA2";"21020180123155514000000000000000002";"210"
"SA4";"21020180123155514000000000000000002";"210";"200000001"
"SA5";"21020180123155514000000000000000002";"210";"200000001";"140000001";"ZZ"
"SA1";"21020180123155522000000000000000002"
"SA2";"21020180123155522000000000000000002";"210"
"SA4";"21020180123155522000000000000000002";"210";"200000001"
"SA5";"21020180123155522000000000000000002";"210";"200000001";"140000671";"ZZ"
"SA1";"21020180123155567000000000000000002"
"SA2";"21020180123155567000000000000000002";"210"
"SA4";"21020180123155567000000000000000002";"210";"200000001"
"SA5";"21020180123155567000000000000000002";"210";"200000001";"140000001";"ZZ"
因此,第二个字段中的值(分隔符';')标记属于一起的数据,值140000001或140000671是触发器。所以结果应该是:
第1个圆角:140000001.http
"SA1";"21020180123155514000000000000000002"
"SA2";"21020180123155514000000000000000002";"210"
"SA4";"21020180123155514000000000000000002";"210";"200000001"
"SA5";"21020180123155514000000000000000002";"210";"200000001";"140000001";"ZZ"
"SA1";"21020180123155567000000000000000002"
"SA2";"21020180123155567000000000000000002";"210"
"SA4";"21020180123155567000000000000000002";"210";"200000001"
"SA5";"21020180123155567000000000000000002";"210";"200000001";"140000001";"ZZ"
第二个文件:140000671.txt
"SA1";"21020180123155522000000000000000002"
"SA2";"21020180123155522000000000000000002";"210"
"SA4";"21020180123155522000000000000000002";"210";"200000001"
"SA5";"21020180123155522000000000000000002";"210";"200000001";"140000671";"ZZ"
现在我找到了一个片段,它通过第二个字段拆分大文件:
$src = "C:\temp\ORD001.txt"
$dstDir = "C:\temp\files\"
Remove-Item -Path "$dstDir\\*"
$header = Get-Content -Path $src | select -First 1
Get-Content -Path $src | select -Skip 1 | foreach {
$file = "$(($_ -split ";")[1]).txt"
Write-Verbose "Wrting to $file"
$file = $file.Replace('"',"")
if (-not (Test-Path -Path $dstDir\$file))
{
Out-File -FilePath $dstDir\$file -InputObject $header -Encoding ascii
}
$file -replace '"', ""
Out-File -FilePath $dstDir\$file -InputObject $_ -Encoding ascii -Append
}
其余的我站在黑暗中。请帮忙。
如果您还不知道,Import-CSV
cmdlet将在此处运行。我会使用它,因为它将所有行作为数组中的不同对象返回,属性是列值。而且您不必手动删除引号等。假设第二列是日期时间值,并且对于每组连续4行应该是唯一的,那么这将起作用:
$src = "C:\temp\ORD001.txt"
$dstDir = "C:\temp\files\"
Remove-Item -Path "$dstDir\*"
$csv = Import-CSV $src -Delimiter ';'
$DateTimeGroups = $csv | Group-Object -Property 'ColumnTwoHeader'
foreach ($group in $DateTimeGroups) {
$filename = $group.Group.'ColumnFiveHeader' | select -Unique
$group.Group | Export-CSV "$dstDir\$filename.txt" -Append -NoTypeInformation
}
但是,如果其中两个“连续4行的组”中的两个具有第二列和第五列的相同值,则会中断。除非您确定每个时间组中始终有4个连续的行,否则无法解决此问题。在这种情况下:
$src = "C:\temp\ORD001.txt"
$dstDir = "C:\temp\files\"
Remove-Item -Path "$dstDir\*"
$csv = Import-CSV $src -Delimiter ';'
if ($csv.count % 4 -ne 0) {
Write-Error "CSV does not have a proper number of rows. Attempting to continue will be bad :)"
return
}
for ($i = 0 ; $i -lt $csv.Count ; $i=$i+4) {
$group = $csv[$i..($i+4)]
$group | Export-Csv "$dstDir\$($group[3].'ColumnFiveHeader').txt" -Append -NoTypeInformation
}
一定要用适当的值替换Column2Header
和Column5Header
。
如果性能不是问题,将Import-Csv
/ Export-Csv
与Group-Object
结合使用,可以使用PowerShell将CSV转换为对象并返回的能力,最简洁,直接地表达您的意图:
$src = "C:\temp\ORD001.txt" # Input CSV file
$dstDir = "C:\temp\files" # Output directory
# Delete previous output files, if necessary.
Remove-Item -Path "$dstDir\*" -WhatIf
# Import the source CSV into custom objects with properties named for the columns.
# Note: The assumption is that your CSV header line defines columns "Col1", "Col2", ...
Import-Csv $src -Delimiter ';' |
# Group the resulting objects by column 2
Group-Object -Property Col2 |
ForEach-Object { # Process each resulting group.
# Determine the output filename via the group's last row's column 5 value.
$outFile = '{0}\{1}.txt' -f $dstDir, $_.Group[-1].Col5
# Append the group at hand to the target file.
$_.Group | Export-Csv -Append -Encoding Ascii $outFile -Delimiter ';' -NoTypeInformation
}
注意:
140000001
)对不起,但我没有标题栏。它是一个以分号分隔的接口文本文件