Cout 在 std_lib_facilities 中未声明

问题描述 投票:0回答:2

我正在尝试使用

std_lib_facilities
标头编写一些基本代码,但显然我做错了。尝试编译此代码:

#include "../std_lib_facilities.h"
#include "stdafx.h"

int main()
{
    cout << "Hello, World!\n";
    return 0;
}

导致此编译错误:

Error   C2065   'cout': undeclared identifier

std_lib_facilities
标头位于项目文件夹中,并且它在 Visual Studio 上似乎已正确配置,因为它出现在项目“标头”选项卡上。以下是
std_lib_facilities
的内容:

/*
   std_lib_facilities.h
*/

/*
    simple "Programming: Principles and Practice using C++ (second edition)" course header to
    be used for the first few weeks.
    It provides the most common standard headers (in the global namespace)
    and minimal exception/error support.

    Students: please don't try to understand the details of headers just yet.
    All will be explained. This header is primarily used so that you don't have
    to understand every concept all at once.

    By Chapter 10, you don't need this file and after Chapter 21, you'll understand it

    Revised April 25, 2010: simple_error() added
    
    Revised November 25 2013: remove support for pre-C++11 compilers, use C++11: <chrono>
    Revised November 28 2013: add a few container algorithms
    Revised June 8 2014: added #ifndef to workaround Microsoft C++11 weakness
*/

#ifndef H112
#define H112 251113L


#include<iostream>
#include<iomanip>
#include<fstream>
#include<sstream>
#include<cmath>
#include<cstdlib>
#include<string>
#include<list>
#include <forward_list>
#include<vector>
#include<unordered_map>
#include<algorithm>
#include <array>
#include <regex>
#include<random>
#include<stdexcept>

//------------------------------------------------------------------------------


//------------------------------------------------------------------------------

typedef long Unicode;

//------------------------------------------------------------------------------

using namespace std;

template<class T> string to_string(const T& t)
{
    ostringstream os;
    os << t;
    return os.str();
}

struct Range_error : out_of_range { // enhanced vector range error reporting
    int index;
    Range_error(int i) :out_of_range("Range error: "+to_string(i)), index(i) { }
};


// trivially range-checked vector (no iterator checking):
template< class T> struct Vector : public std::vector<T> {
    using size_type = typename std::vector<T>::size_type;

#ifdef _MSC_VER
    // microsoft doesn't yet support C++11 inheriting constructors
    Vector() { }
    explicit Vector(size_type n) :std::vector<T>(n) {}
    Vector(size_type n, const T& v) :std::vector<T>(n,v) {}
    template <class I>
    Vector(I first, I last) : std::vector<T>(first, last) {}
    Vector(initializer_list<T> list) : std::vector<T>(list) {}
#else
    using std::vector<T>::vector;   // inheriting constructor
#endif

    T& operator[](unsigned int i) // rather than return at(i);
    {
        if (i<0||this->size()<=i) throw Range_error(i);
        return std::vector<T>::operator[](i);
    }
    const T& operator[](unsigned int i) const
    {
        if (i<0||this->size()<=i) throw Range_error(i);
        return std::vector<T>::operator[](i);
    }
};

// disgusting macro hack to get a range checked vector:
#define vector Vector

// trivially range-checked string (no iterator checking):
struct String : std::string {
    using size_type = std::string::size_type;
//  using string::string;

    char& operator[](unsigned int i) // rather than return at(i);
    {
        if (i<0||size()<=i) throw Range_error(i);
        return std::string::operator[](i);
    }

    const char& operator[](unsigned int i) const
    {
        if (i<0||size()<=i) throw Range_error(i);
        return std::string::operator[](i);
    }
};


namespace std {

    template<> struct hash<String>
    {
        size_t operator()(const String& s) const
        {
            return hash<std::string>()(s);
        }
    };

} // of namespace std


struct Exit : runtime_error {
    Exit(): runtime_error("Exit") {}
};

// error() simply disguises throws:
inline void error(const string& s)
{
    throw runtime_error(s);
}

inline void error(const string& s, const string& s2)
{
    error(s+s2);
}

inline void error(const string& s, int i)
{
    ostringstream os;
    os << s <<": " << i;
    error(os.str());
}


template<class T> char* as_bytes(T& i)  // needed for binary I/O
{
    void* addr = &i;    // get the address of the first byte
                        // of memory used to store the object
    return static_cast<char*>(addr); // treat that memory as bytes
}


inline void keep_window_open()
{
    cin.clear();
    cout << "Please enter a character to exit\n";
    char ch;
    cin >> ch;
    return;
}

inline void keep_window_open(string s)
{
    if (s=="") return;
    cin.clear();
    cin.ignore(120,'\n');
    for (;;) {
        cout << "Please enter " << s << " to exit\n";
        string ss;
        while (cin >> ss && ss!=s)
            cout << "Please enter " << s << " to exit\n";
        return;
    }
}



// error function to be used (only) until error() is introduced in Chapter 5:
inline void simple_error(string s)  // write ``error: s and exit program
{
    cerr << "error: " << s << '\n';
    keep_window_open();     // for some Windows environments
    exit(1);
}

// make std::min() and std::max() accessible on systems with antisocial macros:
#undef min
#undef max


// run-time checked narrowing cast (type conversion). See ???.
template<class R, class A> R narrow_cast(const A& a)
{
    R r = R(a);
    if (A(r)!=a) error(string("info loss"));
    return r;
}

// random number generators. See 24.7.



inline int randint(int min, int max) { static default_random_engine ran; return uniform_int_distribution<>{min, max}(ran); }

inline int randint(int max) { return randint(0, max); }

//inline double sqrt(int x) { return sqrt(double(x)); } // to match C++0x

// container algorithms. See 21.9.

template<typename C>
using Value_type = typename C::value_type;

template<typename C>
using Iterator = typename C::iterator;

template<typename C>
    // requires Container<C>()
void sort(C& c)
{
    std::sort(c.begin(), c.end());
}

template<typename C, typename Pred>
// requires Container<C>() && Binary_Predicate<Value_type<C>>()
void sort(C& c, Pred p)
{
    std::sort(c.begin(), c.end(), p);
}

template<typename C, typename Val>
    // requires Container<C>() && Equality_comparable<C,Val>()
Iterator<C> find(C& c, Val v)
{
    return std::find(c.begin(), c.end(), v);
}

template<typename C, typename Pred>
// requires Container<C>() && Predicate<Pred,Value_type<C>>()
Iterator<C> find_if(C& c, Pred p)
{
    return std::find_if(c.begin(), c.end(), p);
}

#endif //H112

我做错了什么吗?

c++ header cout undeclared-identifier
2个回答
2
投票

我发现您在

../std_lib_facilities.h
之前添加了
stdafx.h
。让我们考虑一下
stdafx.h
是什么。这是一个预编译头

stdafx.h 是由 Microsoft Visual Studio IDE 向导生成的文件,它描述了标准系统和项目特定的包含文件,这些文件经常使用但很少更改。

兼容的编译器(例如,Visual C++ 6.0 及更高版本)将预编译此文件以减少总体编译时间。 Visual C++ 不会编译源文件中 #include "stdafx.h" 之前的任何内容,除非未选中编译选项 /Yu'stdafx.h'(默认情况下);它假设源代码中直到并包括该行的所有代码都已编译。

如果包含标准头文件的部分未编译,则会出现缺少声明的错误。

解决方案:在文件顶部包含

stdafx.h
,或者根本不使用预编译头,或者确保未选中相应的选项。


2
投票

using std::cout;
using namespace std;
放入包含
main ()
函数的文件中。 或者只需在每次出现
cout
时添加
std::
前缀即可。

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