Google App Engine：如何使用send_mail发送html

Question

我有一个带有一种 REST API 的应用程序，我用它来发送电子邮件。然而它目前只发送文本电子邮件，所以我需要知道如何修改它并使其发送 html 。下面是代码：

from __future__ import with_statement

#!/usr/bin/env python
#

import cgi
import os
import logging
import contextlib
from xml.dom import minidom
from xml.dom.minidom import Document
import exceptions
import warnings
import imghdr
from google.appengine.api import images
from google.appengine.api import users
from google.appengine.ext import db
from google.appengine.ext import webapp
from google.appengine.ext.webapp.util import run_wsgi_app
from google.appengine.ext.webapp import template
from google.appengine.api import mail
import wsgiref.handlers

# START Constants
CONTENT_TYPE_HEADER = "Content-Type"
CONTENT_TYPE_TEXT = "text/plain"
XML_CONTENT_TYPE = "application/xml"
XML_ENCODING = "utf-8"
"""
Allows you to specify IP addresses and associated "api_key"s to prevent others from using your app.
Storage and Manipulation methods will check for this "api_key" in the POST/GET params.
Retrieval methods don't use it (however you could enable them to use it, but maybe rewrite so you have a "read" key and a "write" key to prevent others from manipulating your data).

Set "AUTH = False" to disable (allowing anyone use your app and CRUD your data).

To generate a hash/api_key visit https://www.grc.com/passwords.htm
To find your ip visit http://www.whatsmyip.org/
"""
AUTH = {
    '000.000.000.000':'JLQ7P5SnTPq7AJvLnUysJmXSeXTrhgaJ',
}
# END Constants

# START Exception Handling
class Error(StandardError):
    pass
class Forbidden(Error):
    pass

logging.getLogger().setLevel(logging.DEBUG)

@contextlib.contextmanager
def mailExcpHandler(ctx):
    try:
        yield {}
    except (ValueError), exc:
        xml_error_response(ctx, 400 ,'app.invalid_parameters', 'The indicated parameters are not valid: ' + exc.message)
    except (Forbidden), exc:
        xml_error_response(ctx, 403 ,'app.forbidden', 'You don\'t have permission to perform this action: ' + exc.message)
    except (Exception), exc:
        xml_error_response(ctx, 500 ,'system.other', 'An unexpected error in the web service has happened: ' + exc.message)

def xml_error_response(ctx, status, error_id, error_msg):
    ctx.error(status)
    doc = Document()
    errorcard = doc.createElement("error")
    errorcard.setAttribute("id", error_id)
    doc.appendChild(errorcard)
    ptext = doc.createTextNode(error_msg)
    errorcard.appendChild(ptext)
    ctx.response.headers[CONTENT_TYPE_HEADER] = XML_CONTENT_TYPE
    ctx.response.out.write(doc.toxml(XML_ENCODING))
# END Exception Handling

# START Helper Methods
def isAuth(ip = None, key = None):
    if AUTH == False:
        return True
    elif AUTH.has_key(ip) and key == AUTH[ip]:
        return True
    else:
        return False

# END Helper Methods


# START Request Handlers
class Send(webapp.RequestHandler):
    def post(self):
        """
        Sends an email based on POST params. It will queue if resources are unavailable at the time.

        Returns "Success"

        POST Args:
            to: the receipent address
            from: the sender address (must be a registered GAE email)
            subject: email subject
            body: email body content
        """
        with mailExcpHandler(self):
            # check authorised
            if isAuth(self.request.remote_addr,self.request.POST.get('api_key')) == False:
                raise Forbidden("Invalid Credentials")

            # read data from request
            mail_to = str(self.request.POST.get('to'))
            mail_from = str(self.request.POST.get('from'))
            mail_subject = str(self.request.POST.get('subject'))
            mail_body = str(self.request.POST.get('body'))

            mail.send_mail(mail_from, mail_to, mail_subject, mail_body)

            self.response.headers[CONTENT_TYPE_HEADER] = CONTENT_TYPE_TEXT
            self.response.out.write("Success")


# END Request Handlers

# START Application
application = webapp.WSGIApplication([
                                                                             ('/send', Send)
                                                                         ],debug=True)

def main():
    run_wsgi_app(application)

if __name__ == '__main__':
    main()

# END Application

Answer 1

查看 send_mail 功能的

电子邮件消息字段

。
这是您需要的参数：

html
HTML 版本的正文内容，适合喜欢 HTML 电子邮件的收件人。

您应该添加

html

输入参数，如下所示：

#Your html body
mail_html_body = '<h1>Hello!</h1>'

# read data from request
mail_to = str(self.request.POST.get('to'))
mail_from = str(self.request.POST.get('from'))
mail_subject = str(self.request.POST.get('subject'))
mail_body = str(self.request.POST.get('body'))

mail.send_mail(mail_from, 
               mail_to,
               mail_subject, 
               mail_body,
               html = mail_html_body ) #your html body

Answer 2

您可以使用EmailMessage类的html字段

message = mail.EmailMessage(sender=emailFrom,subject=emailSubject)
message.to = emailTo
message.body = emailBody
message.html = emailHtml
message.send()