这是我的查询:
SELECT `p`.`name` AS 'postauthor', `a`.`name` AS 'authorname',
`fr`.`pid`, `fp`.`post_topic` AS 'threadname', `fr`.`reason`
FROM `z_forum_reports` `fr`
LEFT JOIN `forums` `f` ON (`f`.`id` = `fr`.`pid`)
LEFT JOIN `forums` `fp` ON (`f`.`first_post` = `fp`.`id`)
LEFT JOIN `ps` `p` ON (`p`.`id` = `f`.`author_guid`)
LEFT JOIN `ps` `a` ON (`a`.`account_id` = `fr`.`author`)
我的问题是这样的左连接:
SELECT `a`.`name`, `a`.`level`
[..]
LEFT JOIN `ps` `a` ON (`a`.`account_id` = `fr`.`author`)
因为,万一a
有很多行,它会返回像我的情况:
NAME | LEVEL
Test1 | 1
Test2 | 120
Test3 | 2
Test4 | 1
我希望它与水平a.name
和限制1 order
选择desc
,所以它会返回更高level
其中(a.account_id = fr.author)
的名称。
希望你有我。如果没有,随意发表评论。
尝试更换:
LEFT JOIN ps a ON a.account_id = fr.author
有:
LEFT JOIN ps a
ON a.PrimaryKey --- the Primary Key of ps
= ( SELECT b.PrimaryKey
FROM ps AS b
WHERE b.account_id = fr.author
ORDER BY b.level DESC
LIMIT 1
)
更换LEFT JOIN子句是这样的:
...
LEFT JOIN (SELECT b.account_id, b.name
FROM (SELECT c.account_id, MAX(c.level) AS level
FROM ps AS c
GROUP BY c.account_id) AS d
JOIN ps AS b ON b.account_id = d.account_id AND b.level = d.level
) AS a
ON (a.account_id = fr.author)
...
这仍将返回多行,如果有在ps
几行具有相同的帐户ID和相同的级别和水平最高水平:
NAME | LEVEL
Test1 | 1
Test2 | 120
Test3 | 2
Test4 | 1
Test5 | 120
如果这种情况可能会出现,那么你必须决定你想要做什么 - 并适当调整查询。例如,你可能会决定一个组使用MAX(b.name)
BY子句中任意选择字母后面的两个名字。